1
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Insert the numbers 1-9 inclusive each only once into the calculation to arrive at the answer 100.

( - ) + + - - - = 100

Is this possible?

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2
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It's

possible: $(68 - 2) + 51 + 3 - 4 - 7 - 9 = 100$

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4
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Here is an alternative answer. The parentheses in the question would be redundant if you only did addition and subtraction (and concatenation). To actually make them useful, I used an implied multiplication:

$$(23-1)5+4+8-6-7-9 \\= 110+4+8-6-7-9 = 100$$

Edit:
If you use two implied multiplications, you don't need concatenation at all:

$$4(9-5)7+1+3-2-6-8\\ = 112+1+3-2-6-8 = 100$$

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