8
$\begingroup$

Here is a puzzle I just heard about.

Nebuchadnezzar x  Methuselah
---------------------------    =   ?
    Melchior + Balthazar
$\endgroup$
  • 2
    $\begingroup$ Looks like you have quite a few valid potential answers! $\endgroup$ – El-Guest Sep 8 '18 at 18:23
  • 2
    $\begingroup$ I think dr jimbob's is clearly the intended one. $\endgroup$ – Gareth McCaughan Sep 8 '18 at 19:16
16
$\begingroup$

These are

large wine bottle sizes specific for sparkling wine.

Specifically,

Melchior = 24 standard bottles,
Nebuchadnezzar = 20 standard bottles,
Balthazar = 16 standard bottles,
Methuselah = 8 standard bottles,
Jeroboam = 4 standard bottles.
Source

So the math works out to give

$\frac{20 \mathrm{bottles} \times 8 \mathrm{bottles}}{24\mathrm{bottles}+16 \mathrm{bottles}} = \frac{160\mathrm{bottles}^{2}}{40\mathrm{bottles}} = 4 \mathrm{bottles}$

Which going back to the word equivalency we find is equal to the word:

Jeroboam

$\endgroup$
  • $\begingroup$ (Thanks. Was having trouble getting the spoiler formatting working.) $\endgroup$ – dr jimbob Sep 8 '18 at 18:17
  • $\begingroup$ No problem! The spoilers are funny, they are indeed >! but you can't have consecutive lines of >! unless you have <pre> or some funny code before and after it. I like personally spacing things out with non-spoiler words. $\endgroup$ – El-Guest Sep 8 '18 at 18:19
  • 1
    $\begingroup$ This is definitely the right answer in my view. Congratulations. $\endgroup$ – Anush Sep 8 '18 at 19:24
7
$\begingroup$

The answer is

306.

This is because

of the ages of the men when they died: Nebuchadnezzar was 72; Methuselah was 969; Melchior was 116; and Balthazar was 112.

So the math works out to

$\frac{72 \times 969}{116 + 112} = 306$.

$\endgroup$
  • $\begingroup$ Wow. Even though this wasn't the answer, it's pretty remarkable that you got an integer out of that. $\endgroup$ – greenturtle3141 Sep 9 '18 at 16:09
  • $\begingroup$ @greenturtle3141 I was stunned when it worked out like that — to be honest, if it didn’t I might’ve not posted it haha! $\endgroup$ – El-Guest Sep 9 '18 at 16:14
5
$\begingroup$

I'm not sure if my answer is right, but this could be a variation

If we take the number word of each word (i.e. a=1, 26=z) and do the math we get: (148*112)/(83+89), to 96.3720930233

$\endgroup$

Your Answer

By clicking “Post Your Answer”, you agree to our terms of service, privacy policy and cookie policy

Not the answer you're looking for? Browse other questions tagged or ask your own question.