3x3 cube with no center square so 26 cubes, You can start where ever you like and need to visit every room(cube exactly once)

A valid operation is going any adjacent cube that is not diagonally adjacent.

How would you solve this?

  • $\begingroup$ you mean a 3 x 3 x 3 cube with no center square on each face? with 6 faces on the cube, each missing the center cube, that would be 8 cubes per face, 6 cubes = 48 cubes, in total.... right? $\endgroup$ – rm-vanda Sep 5 '18 at 21:00
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    $\begingroup$ @rm-vanda wrong, that would be 8 squares per face, but there would be 26 cubes total in the 3x3x3 structure. $\endgroup$ – Quintec Sep 5 '18 at 21:01
  • $\begingroup$ Oh, yes, I was thinking "rooms" === "cubes" === "squares" - thanks for clarifying $\endgroup$ – rm-vanda Sep 5 '18 at 21:03
  • $\begingroup$ @gnovice I didn't tag this question as a duplicate because the constraints are not the same. There you have to begin with the central cube of a face and end in the center of the 3x3 cube. Here you can begin and end wherever you like. $\endgroup$ – xhienne Sep 5 '18 at 22:13
  • $\begingroup$ Damn you are right. Unfortunatly, I have already marked it as equivalent to another question, and I can't roll it back $\endgroup$ – Conrad Getty Sep 5 '18 at 22:59

The answer is

there is no solution.

See this answer to another puzzle. The problem is slightly different but the reasoning is the same.


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