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Previous Puzzles(Not linked to this one): Simple Math Problem #1 and Simple Math Problem #2

Prove the equation:

$-6439832+ = 9$

$-$ and $+$ are there just to tell that you can use only these two operations. Also no need to separate or rearrange numbers, just solve it in steps(Use operations alternately).

Example:

enter image description here

Hint 1:

The 1st and last go together and off, now turn of next 1st and last.

Hint 2:

The operator is with end operands only [use end operands(one after other) to create new number] and use operators alternately!

Sorry if too easy or not good. Enjoy:)

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6
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    $\begingroup$ I have absolutely no idea what this question is asking! $\endgroup$
    – JMP
    Commented Aug 31, 2018 at 3:04
  • $\begingroup$ Sorry for that, See @sedricks answer he atleast got the idea!! $\endgroup$
    – Preet
    Commented Aug 31, 2018 at 3:05
  • $\begingroup$ so is @sedrick the right answer then? $\endgroup$
    – JMP
    Commented Aug 31, 2018 at 3:07
  • $\begingroup$ @JonMarkPerry, he just got idea, I said use operations alternately but he mixed up them. If it makes any sense to you now $\endgroup$
    – Preet
    Commented Aug 31, 2018 at 3:09
  • $\begingroup$ How can we create a second number, without separating the original number? We need two numbers for +/- operation. I did not understand that part. $\endgroup$
    – FLash
    Commented Nov 6, 2018 at 8:55

3 Answers 3

4
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Here is my answer:

$ 6 - 4 + 3 - 9 + 8 + 3 + 2 = 9$

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3
  • $\begingroup$ +1 for the right answer but this is not intended solution I said no need to separate numbers I want it to solve in steps like a flow diagram or some kind. $\endgroup$
    – Preet
    Commented Aug 31, 2018 at 2:42
  • $\begingroup$ @Preet, what do you mean by solve it in steps? Do you mean showing each step individually? $\endgroup$
    – SteamCode
    Commented Aug 31, 2018 at 2:43
  • $\begingroup$ sorry if not clear actually create a whole new no. from existing by these operations then again a new no. at last you will get 9. If clear now;) $\endgroup$
    – Preet
    Commented Aug 31, 2018 at 2:44
2
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Is this what you meant by solve it in steps:

$6, 4, 3, 9, 8, 3, 2$
$10, 1, 12, 1, 5, 1$
$9, 13, 11, 6, 6$
$4, 2, 5, 0$
$2, 3, 5$
$1, 8$
$9$

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5
  • $\begingroup$ could you show the operations that you used? I'm a little confused $\endgroup$
    – SteamCode
    Commented Aug 31, 2018 at 2:54
  • $\begingroup$ From first line to second line: 6+4, 4-3, 3+9, 9-8, 8-3, 3-2 $\endgroup$
    – sedrick
    Commented Aug 31, 2018 at 2:55
  • $\begingroup$ You got the idea but I think you are wrong in two steps of first row if i got it! Try to use operations alternatively. +1 $\endgroup$
    – Preet
    Commented Aug 31, 2018 at 2:57
  • $\begingroup$ What does "Use operations alternatively" mean? Do you perhaps mean alternately? $\endgroup$
    – sedrick
    Commented Aug 31, 2018 at 3:00
  • $\begingroup$ yeah my bad i always confuse these two;) $\endgroup$
    – Preet
    Commented Aug 31, 2018 at 3:02
1
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Alternating plus and minus, like kraby15

6 + 4 - 3 + 9 - 8 + 3 - 2 = 9

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