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Can You prove it that 7 + 7 = 12

partially mathematical

EDIT (Due to answer): By 7 and 12 I mean the Numbers.

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closed as too broad by JMP, Bass, Saeïdryl, Jaap Scherphuis, A J Aug 27 '18 at 11:56

Please edit the question to limit it to a specific problem with enough detail to identify an adequate answer. Avoid asking multiple distinct questions at once. See the How to Ask page for help clarifying this question. If this question can be reworded to fit the rules in the help center, please edit the question.

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    $\begingroup$ Related and maybe duplicate: How to cut 12 in half and get 7 $\endgroup$ – A J Aug 27 '18 at 11:04
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    $\begingroup$ There is an answer already on the linked question, which can answer yours too. $\endgroup$ – A J Aug 27 '18 at 11:09
  • $\begingroup$ @AJ if anyone, you should explain in an answer just as it is explained in the link (as well as including the link, itself, for credibility) :P $\endgroup$ – Feeds Aug 27 '18 at 11:10
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    $\begingroup$ As the puzzle is now stated, there are several ways to "prove" this, and no way to tell, which of them is the one intended as correct. This makes the puzzle too broad, so maybe include some additional constraints on allowed proof methods? Moving the goalposts (so that otherwise valid answers get retroactively disqualified) is generally frowned upon: it's better to add the constraints beforehand, and then accept any answer that fits all of them, even if the answer wasn't the one you intended. $\endgroup$ – Bass Aug 27 '18 at 11:16
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    $\begingroup$ Possible duplicate of How to cut 12 in half and get 7 $\endgroup$ – Saeïdryl Aug 27 '18 at 11:23
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Answer 1:

Since there is no base specified, I'm going to pick base 12.
$7_{12} + 7_{12} = 12_{12}$

Answer 2:

Roman numerals..

My lateral thinking:

7 = VII
Flip it and you also get 7 = ΛII
put them one under the other like you learned in school and you get
VII
ΛII
put them really close together and you get
XII = 12.

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  • $\begingroup$ Isn't that what has already been in an answer to the linked question? (laterally, of course). :P $\endgroup$ – A J Aug 27 '18 at 11:55
  • $\begingroup$ Yes. In my defense, I saw the link to the duplicate question after I wrote the answer. That's why I added another answer as well. $\endgroup$ – Marius Aug 27 '18 at 12:09
  • $\begingroup$ Your First Answer is Correct $\endgroup$ – Holyprogrammer Aug 28 '18 at 6:06
  • $\begingroup$ @KhushrajRathod So is the second one. The first one is just what you expected :) $\endgroup$ – Marius Aug 28 '18 at 6:34
  • $\begingroup$ @Marius Yes that is what I meant :p $\endgroup$ – Holyprogrammer Aug 28 '18 at 10:18
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12 what?

If you ask for corners yes it´s true. The number 7 has 6 corners,
so 6 corners + 6 corners = 12 corners

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  • $\begingroup$ Nice try, but wrong answer sorry :|. I mean the number 12 $\endgroup$ – Holyprogrammer Aug 27 '18 at 10:56
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    $\begingroup$ @KhushrajRathod You have to be careful if you're using the tag lateral thinking :D $\endgroup$ – Doomenik Aug 27 '18 at 10:59
  • $\begingroup$ how 7 has six corners ? $\endgroup$ – Amruth A Aug 27 '18 at 11:01
  • $\begingroup$ @AmruthA by counting? Or is edges a better fitting word (No native speaker) $\endgroup$ – Doomenik Aug 27 '18 at 11:02
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Suppose that

It is $12$:$00$ on an analog clock.

Then,

Once the clock strikes $1$:$00$, the big hand would have moved directly above the small hand. Let's call this position $1$.

When the clock strikes $2$:$00$, we now have a total of $1+1$ positions, which is $2$.

The pattern is obvious; when the clock strikes $7$:$00$, the big hand would have moved directly on top the small hand $7$ times.

Note that

O'clock means $12$.

Therefore,

$7+7=12$.

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  • $\begingroup$ @downvoter may you please share why you downvoted? Was it because of something I did wrong or was it because you didn't like the answer? $\endgroup$ – Feeds Aug 27 '18 at 12:51

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