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Today, I have what I consider a tricky riddle for you to answer. Please note, I have added the correct tags to this riddle.

I have some math problems that I need help solving. Do you think you'd be able to help me? I think I can solve the first two, but I'm struggling with the rest, especially the last question.

Please solve the problems below. No calculators may be used when solving these problems.
18. logbin(1809) = 212
19. d/dx F(x) = 912x4 - 12x3 + 123x2 - 255x + 18
20. Make the statement true: 5 (?) 12 (?) 5 (?) 16 (?) 8 (?) 1 (?) 14 (?) 20 = 1854
21. How is the following true? 65 - 61 = 6

Using the above answers, please solve for the following:
22. A man with two friends named Parker and Ford, goes into a photo booth looking to take some pictures with his friends. Each ticket booth takes a picture once every half second, and the timer of the ticket booth is 4.15 minutes per person in the booth. If each picture taken is 5 cents, then how tall was the first man?

Bonus:
If you can actually solve the problems, that would be cool too, though that's not as important.

Hint:

It may seem daunting at first to tackle this riddle, but just take a closer look at each line. It may not be as difficult as you think it is. No math is needed to solve this puzzle.

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  • $\begingroup$ Joe, you come up with some crafty puzzles! +1 $\endgroup$
    – Taco
    Commented Aug 23, 2018 at 16:20
  • $\begingroup$ @PerpetualJ, thanks, I try my best :) $\endgroup$
    – Joe-You-Know
    Commented Aug 23, 2018 at 16:22

2 Answers 2

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I don't think this part needs a spoiler tag:

6 ft 4 in

18.

So I don't understand most of the clues, but I do know this is referencing Abraham Lincoln. The first clue is about him being born in a log cabin in 1809

20.

Elected in 1854

21.

1861 - Start of the Civil War, 1865, second inaugural address

22.

Ford's Theater, bodyguard John Parker and assassin John Wilkes Booth

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  • $\begingroup$ That is correct, though you are missing some stuff I threw in there. Take El-Guest for example, he solved one of the clues. $\endgroup$
    – Joe-You-Know
    Commented Aug 23, 2018 at 18:32
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    $\begingroup$ @Joe-You-Know Cool! This is the first puzzle on SE that I've solved first :) $\endgroup$
    – Chris Sunami
    Commented Aug 23, 2018 at 18:38
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@Chris Sunami has had some good suggestions which I'll try to flesh out a bit more:

Is your name

ABRAHAM LINCOLN?

18.

Abe Lincoln was born in a log cabin on February 12, 1809 (1809-2-12).

19.

The A1Z26 of the numbers 9-12-12-1-23-25-5-18 read "IL LAWYER", because Abe Lincoln was a lawyer from Illinois.

20.

The A1Z26 translation of the numbers read "ELEPHANT = 1854", because the Elephant (Republican) party was founded in 1854. (That said, Lincoln wasn't elected leader of it until 1859-1860ish.)

    21.

Abraham Lincoln was president (the 16th president) from 1861 to 1865. 65-61 = 6, because at the end of Pres. Lincoln's term, he was 6 feet underground (credit to @Joe-You-Know for the macabre humour!)

    22.

This contains references to Lincoln's substitute bodyguard, John Parker, and Ford's Theatre; where Lincoln was shot by John Wilkes Booth.

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    $\begingroup$ You're right, this is where I have a good chuckle and tell you that you're wildly, wildly off base save for problem 20. Everything before the equals sign is correct, but after that, it is just a number, which doesn't need to be deciphered. $\endgroup$
    – Joe-You-Know
    Commented Aug 23, 2018 at 18:12
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    $\begingroup$ The lateral thinking tag is heavily used in this puzzle. $\endgroup$
    – Joe-You-Know
    Commented Aug 23, 2018 at 18:14
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    $\begingroup$ But decoding 1854 as red seems to be quite fitting ... $\endgroup$
    – M Oehm
    Commented Aug 23, 2018 at 18:27
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    $\begingroup$ @El-Guest, well, I was kind of making an ill-tasting joke for 65-61 = 6. 6 representing, 6 feet under. $\endgroup$
    – Joe-You-Know
    Commented Aug 23, 2018 at 20:04
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    $\begingroup$ @Joe-You-Know, quite honestly, I wish I could upvote your question twice, just for that joke. Since I can't +2, please have a complimentary 10/10. $\endgroup$
    – El-Guest
    Commented Aug 23, 2018 at 20:28

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