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- Pirate's Golden Throw 2 answers
Nine Pirates are splitting 99 gold coins among them. Each of them has already one extra gold coin in their pockets.
Starting from 1st pirate, each will make a proposal on how many coins will be given to each of them.
If the majority (including proposer) accept the proposal then the game ends and the split will be done accordingly.
If not accepted, the proposer will be eliminated and punished to pay an extra coin to the winner, and the next pirate will follow the same procedure together with the remaining pirates.
The winner of the game will be the one who has the highest number of coins at the end!
As you guess, pirates are absurdly very smart and supposed to play the game optimally and trying to make as many coins as possible at the end of the game.
At the end of the game, how many coins will each of the pirates have?
Note: You may name the pirates as you like, such as A, B, C, or 1st, 2nd, 3rd etc. and the majority means more than 50%.