# Find 93 using first 4 prime numbers

Using operators plus (+), minus (-), multiplication (x) and division (/), power function/exponentiation (^) and as many brackets as you want, can you find

A formula which uses 2,3,5,7 to make 93?

• I would be able to do it with two $2$s; i.e., $5^3-2^{7-2}=93$. (The same goes for two $5$s since $7-2=5$.) Also, including concatenation, I could create another formula with two $2$s: $57+(2\times 3)^2$, and another: $75+(2\times 3^2)$, and yet another: $23 + (2\times 5\times 7)$, and even another: $73 + (5\times 2^2)$. – Mr Pie Jul 31 '18 at 11:09
• I finally was able to make one, but it uses a $0$. $$7^3-250=93.$$ That's the best I can do without using @Glorfindel 's answer. – Mr Pie Jul 31 '18 at 11:19
• @user477343 Glorfindel's answer is unique :) – Oray Jul 31 '18 at 11:20
• Indeed... but is there a way to prove that his answer is the only one that satisfies the puzzle? – Mr Pie Jul 31 '18 at 11:20
• @user477343 yes coding. – Oray Jul 31 '18 at 11:21

$2^7 - 35 = 93$ works.