This is a relatively easy puzzle, but I thought I might share it anyhow.

If 5 is 4, 6 is 9, and 7 is 5, what is 8?

Hint 1:

The title gives a clue (not directly to the answer, but to the general rule.)

Hint 2:

SPQR up!

  • $\begingroup$ Title has identity so perhaps it's $1$? $\endgroup$ – TheSimpliFire Jul 9 '18 at 18:44
  • $\begingroup$ Edited Hint 1 for clarity. $\endgroup$ – akr Jul 9 '18 at 18:46

The answer is that 8 =



we are looking at Roman numerals embedded in the written-out form of the number's name. fIVe=IV=4, sIX=IX=9, seVen=V=5. So eIght=I=1.

  • $\begingroup$ Perfect! Exactly my answer. $\endgroup$ – akr Jul 9 '18 at 18:48

I'll give it a shot:

8 is 25.


'five' contains 4 letters
'six' contains 3 letters -> squared is 9
'seven' contains 5 letters
So basically just how many letters, and if the number is even, square it.

  • $\begingroup$ Not quite my reasoning, but close! The same, simple rule applies to all of them. $\endgroup$ – akr Jul 9 '18 at 18:39

You could also have that



$5$ has two lines and one curve. If the curve means 'subtract one line' then the result is $5$ minus $2-1$ which is $4$.

Similarly, $7$ has two lines. The result is $7$ minus $2$ which is $5$.

So the rule for odd number is *odd number - (number of lines - number of curves)

For the even numbers, it could just be that they are flipped upside-down, in which case $6$ is $9$ and $8$ remains the same.

  • $\begingroup$ Not quite! But good try! $\endgroup$ – akr Jul 9 '18 at 18:40

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