5
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I am a 4 digit number
The sum of my digits is half of me
Add a tail to one of my digit-members
Then the sum of them is three

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10
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I am a 4 digit number

1811

The sum of my digits is half of me

1 + 8 + 1 + 1 = 11 and 11 is laterally half of 18|11

Add a tail to one of my digit-members

A tall tale is adding a tail to 8 gives &

Then the sum of them is three

1&11 is 12 with a digit sum of 3

The Beginnings of Galois Theory

Évariste Galois 1811 - 1832

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  • $\begingroup$ This absolutely much be right and is very ingenious, but I'm 100% unconvinced by the "add a tail" bit. (I don't mean that you're wrong, I mean I don't like that element of the puzzle.) Nice puzzle otherwise, though. $\endgroup$ – Gareth McCaughan May 12 '18 at 10:50
  • $\begingroup$ @GarethMcCaughan Perhaps it's a rot13 svfu tail. $\endgroup$ – Tom May 12 '18 at 12:28
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    $\begingroup$ By this logic even 1181 is also a viable candidate. $\endgroup$ – Mea Culpa Nay May 12 '18 at 17:41
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    $\begingroup$ @MeaCulpaNay rot13(Tnybvf jnf abg obea va ryrira uhaqerq rvtugl bar ohg rvtugrra uhaqerq ryrira.) :-). $\endgroup$ – swihart May 13 '18 at 16:22
  • $\begingroup$ @GarethMcCaughan rot13(V'z bcra gb fhttrfgvbaf gb gvtugra hc gung "gnvy" ybtvp - qb lbh unir nal?) $\endgroup$ – swihart May 13 '18 at 16:25
-1
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Here is a wild, wilder and wildest guess:

It is a Roman numeral and it is VIII.

As,

The value of it is 8 and the number of individual digits is 4, which is half of 8.

Also,

When you add a tail to the last one(I) to make it VIIX(Though stretched a bit), whose value becomes 10 - 7 ( X - VII), though not by an accepted rules, but by lateral thinking...it results in 3.

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  • 4
    $\begingroup$ Cmiiw, but the sum of your individual digits is not half of the number itself; it's equal instead. $\endgroup$ – athin May 12 '18 at 4:25

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