# The Beginnings of Galois Theory

I am a 4 digit number
The sum of my digits is half of me
Add a tail to one of my digit-members
Then the sum of them is three

I am a 4 digit number

1811

The sum of my digits is half of me

1 + 8 + 1 + 1 = 11 and 11 is laterally half of 18|11

Add a tail to one of my digit-members

A tall tale is adding a tail to 8 gives &

Then the sum of them is three

1&11 is 12 with a digit sum of 3

The Beginnings of Galois Theory

Évariste Galois 1811 - 1832

• This absolutely much be right and is very ingenious, but I'm 100% unconvinced by the "add a tail" bit. (I don't mean that you're wrong, I mean I don't like that element of the puzzle.) Nice puzzle otherwise, though. Commented May 12, 2018 at 10:50
• @GarethMcCaughan Perhaps it's a rot13 svfu tail.
– Tom
Commented May 12, 2018 at 12:28
• By this logic even 1181 is also a viable candidate. Commented May 12, 2018 at 17:41
• @MeaCulpaNay rot13(Tnybvf jnf abg obea va ryrira uhaqerq rvtugl bar ohg rvtugrra uhaqerq ryrira.) :-). Commented May 13, 2018 at 16:22
• @GarethMcCaughan rot13(V'z bcra gb fhttrfgvbaf gb gvtugra hc gung "gnvy" ybtvp - qb lbh unir nal?) Commented May 13, 2018 at 16:25

Here is a wild, wilder and wildest guess:

It is a Roman numeral and it is VIII.

As,

The value of it is 8 and the number of individual digits is 4, which is half of 8.

Also,

When you add a tail to the last one(I) to make it VIIX(Though stretched a bit), whose value becomes 10 - 7 ( X - VII), though not by an accepted rules, but by lateral thinking...it results in 3.

• Cmiiw, but the sum of your individual digits is not half of the number itself; it's equal instead. Commented May 12, 2018 at 4:25