This is not the usual $8, 5, 4, 9, 1, 7, 6, 3, 2, 0$ sequence puzzle, which the answer of the pattern is

Numbers are in alphabetical order

The sequence is: $3, 9, 1, 5, 7, 0, 2, 4, 8, 6$. Can you figure the pattern of this sequence?


It's in alphabetical order by the last letter. E, E, E, E, N, O, O, R, T, X

  • 19
    $\begingroup$ Isn't that ambiguous? I think the correct answer is that they are in alphabetical order when written backwards. $\endgroup$ – noedne Apr 25 '18 at 2:03
  • $\begingroup$ That is also true, but I think my answer is acceptable as well. :P $\endgroup$ – kraby15 Apr 25 '18 at 2:04
  • 13
    $\begingroup$ But it doesn't differentiate the sequence from, say, the same sequence with the first four numbers rearranged in a different order. $\endgroup$ – noedne Apr 25 '18 at 2:06
  • $\begingroup$ Well in that case, neither does writing each number backwards differentiate the original sequence from another sequence that has the first four numbers mixed. $\endgroup$ – kraby15 Apr 25 '18 at 2:09
  • 1
    $\begingroup$ The second sequence has the property that the last letters of its numbers are in alphabetical order, but not the property that its numbers are in alphabetical order when written backward. $\endgroup$ – noedne Apr 25 '18 at 2:11

Observation (not full answer):

first 5 numbers are odd, last 5 are even.


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