4
$\begingroup$

A rabbit saw 6 elephants while going to the river. Every elephant saw 2 monkeys going to the river. Every monkey has 1 parrot each. How many of animals went to the river?

$\endgroup$
  • 1
    $\begingroup$ As this is a popular puzzle you should at least point to the source or mention it. $\endgroup$ – rhsquared Apr 6 '18 at 13:59
7
$\begingroup$

5

but there's no definite answer without a few assumptions:

1 rabbit
0 elephants (it is never said they are going to the river)
2 monkeys (assuming all the elephants saw the same monkeys)
2 parrots (assuming a monkey having a parrot means 'is currently in possession of')

| improve this answer | |
$\endgroup$
  • 3
    $\begingroup$ Also hidden assumption: "All animals going to the river are mentioned in the text" and "a parrot being carried by a monkey still counts as 'going'". $\endgroup$ – Cubic Apr 6 '18 at 15:29
  • $\begingroup$ A small doubt: Dont you think the sentence "1 rabbit saw 6 elephants while going to the river" is ambigious. Its not clear if elephants are going to the river and the rabbit is sitting somewhere or it could be both are in going to the river or only rabbit is going to ther river while elephants are somewhere. I could see 3 possibilities. Am I right? $\endgroup$ – Nagaraju May 20 at 9:01
4
$\begingroup$

The answer is

Indeterminate

because

It is unclear whether or not the elephants were going to the river. I assume that they were not, but simply stating that "a rabbit saw 6 elephants while going to the river" tells us nothing about the location or direction of the elephants. Rephrasing "saw" to "met" would be somewhat less ambiguous (similar to the classic riddle "As I was going to St. Ives ...") that the elephants were travelling in the opposite direction.

also

We are told that the monkeys are going to the river, but we don't know how many monkeys there are. Did the elephants all see the same pair of monkeys (minimum 2) or did they all see separate ones (maximum 12)? There is no way to know based on the information given.

| improve this answer | |
$\endgroup$
  • $\begingroup$ Of course this is the right answer.   Do we know that all mentioned animals have perfect vision?  Do we know how many turkeys and weasels went to the river?    :-)    ⁠ $\endgroup$ – Peregrine Rook Apr 6 '18 at 14:51
  • $\begingroup$ A small doubt: Dont you think the sentence "1 rabbit saw 6 elephants while going to the river" is ambigious. Its not clear if elephants are going to the river and the rabbit is sitting somewhere or it could be both are in going to the river or only rabbit is going to ther river while elephants are somewhere. I could see 3 possibilities. Am I right? $\endgroup$ – Nagaraju May 20 at 9:03
3
$\begingroup$

I think the answer is

3

Given that

Neither the parrots nor the elephants are said to be going to the river (so 1 rabbit plus 2 monkeys).

| improve this answer | |
$\endgroup$
  • $\begingroup$ A small doubt: Dont you think the sentence "1 rabbit saw 6 elephants while going to the river" is ambigious. Its not clear if elephants are going to the river and the rabbit is sitting somewhere or it could be both are in going to the river or only rabbit is going to ther river while elephants are somewhere. I could see 3 possibilities. Am I right? $\endgroup$ – Nagaraju May 20 at 9:03
2
$\begingroup$

I fear I’ve overlooked something, but I believe that the answer is:

25

Breakdown:

\begin{array}{l,c,l}\text{Rabbit(s):}&1&=1\\\text{Elephants:}&1\times6&=6\\\text{Monkeys:}&6\times2&=12\\\text{Parrots:}&12\times1&=12\end{array} $$\text{Total: Rabbit(s) + Monkeys + Parrots} = 1+12+12=25$$ because the elephants were not going to the river.

| improve this answer | |
$\endgroup$
2
$\begingroup$

Further to the previous posts I think that the answer is:

At least 5 animals

because

We know that the rabbit was going to the river, the 2 monkeys were going there and each monkey had a parrot. But we don't know which way the elephants were going. That's why I think the answer should be at least and not exactly 5.

| improve this answer | |
$\endgroup$
1
$\begingroup$

I believe the answer is

13

Reason:

1 Rabbit
6 elephants saw 2 monkeys each, so 6*2 = 12 monkeys
It doesn't mention that elephants are going to the river, and even though the monkeys have parrots, it doesn't say they physically carry them to the river.

| improve this answer | |
$\endgroup$
1
$\begingroup$

I think that there's not really enough information for a single answer, but it's possible to construct a scenario where

There are any odd number from 5 to 25, inclusive.

For example, to get:

11

Imagine this:

In the picture below, the grey ovals are elephants, the red lines are the paths of 5 different monkeys (each holding a parrot), and the purple, dotted line is the path of the rabbit. Each elephant sees two different monkeys (heading to the river), and the rabbit can see all of the elephants. This means there are 5 monkeys, 5 parrots, and 1 rabbit heading towards the river.

enter image description here

| improve this answer | |
$\endgroup$
0
$\begingroup$

I think the answer is

5

Because

A rabbit is 1. The elephants aren't going to the river, so we'll leave them out. Then there are 2 monkeys going to the river. Every monkey has 1 parrot, and there are 2 monkeys, so altogether they have 2 parrots, which are probably going to the river with them. So 1 + 2 + 2 = 5.

Note: got it wrong.

Every elephant saw a monkey. So let's restate this. 1 + (6 x 2) + (2 x 1) = 15.

| improve this answer | |
$\endgroup$
  • $\begingroup$ Please re-examine the final term of your equation (the part after the last +, before the =) and explain why you got an answer different from mine. $\endgroup$ – Peregrine Rook Apr 6 '18 at 14:37
  • $\begingroup$ OH, I see. The amount of monkeys changed, therefore the amount of parrots changed, making the sum larger. $\endgroup$ – KoolKidz112 Apr 6 '18 at 14:45
-2
$\begingroup$

rabbit: 1 + elephant: 6 + monkeys: 2 = 9

| improve this answer | |
$\endgroup$

Not the answer you're looking for? Browse other questions tagged or ask your own question.