-1
$\begingroup$

I am trying to solve this quiz, but it is too hard for me.

What number should I put in place of the question mark?

3   6   2   8
2   1   1   3
1   3   1   4
5   5   3   ?
$\endgroup$
  • 2
    $\begingroup$ Welcome to Puzzling! Where did the quiz come from? - if you didn't create it yourself, could you provide attribution/ a link? $\endgroup$ – puzzledPig Apr 1 '18 at 16:59
  • $\begingroup$ You edited this after accepting an answer, to change the puzzle to something different that invalidates the answer? Why? If you have a new question to ask, ask it as a new question. See the first paragraph of this answer for why changing answered questions is not good. I've rolled back your change. $\endgroup$ – Rubio Apr 2 '18 at 15:29
  • $\begingroup$ Also and has already been mentioned, it looks like you're asking us to solve a puzzle you found elsewhere. For content that you did not create yourself, please provide attribution - at minimum you need to let us know where this came from, and any additional context you can provide is usually a big help to solvers. Posts which use someone else's content without disclosing where it came from are generally deleted. $\endgroup$ – Rubio Apr 2 '18 at 15:29
3
$\begingroup$

It could be

10

Because

The numbers added to get the last column follow the pattern:


X X .
. X X
X X .
. X X

$\endgroup$
  • $\begingroup$ Austin, thank you! I consider that you are wright. I also think about 10. $\endgroup$ – Alex Petrov Apr 1 '18 at 17:30
2
$\begingroup$

I think the answer is

8

with the idea that

the final number in a row is the sum of the highest and lowest values in the rest of the columns in that row:
6+2 = 8
2+1 = 3
3+1 = 4
5+3 = 8

$\endgroup$
  • $\begingroup$ Glorfindel, thank you for your answer! But Austin`s version is closer to the truth. $\endgroup$ – Alex Petrov Apr 1 '18 at 17:33

Your Answer

By clicking “Post Your Answer”, you agree to our terms of service, privacy policy and cookie policy

Not the answer you're looking for? Browse other questions tagged or ask your own question.