Taking a numeral core (digits: a non-quad four) digits I ordered, then lesser I minused, till evolve I couldn't more.
What is this unfathomably clunky poem all about?
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You're referring to:
Quoting from the linked Wikipedia article:
Kaprekar's routine is an algorithm in recreational mathematics which produces a sequence of numbers which either converges to a constant value or results in a repeating cycle. The algorithm is as follows:
1. Choose any natural number $n$ in some base (usually base 10). This is the first number of the sequence.
2. Create a new number $n′$ by arranging the digits of $n$ in descending order, and another new number $n″$ by arranging the digits of $n$ in ascending order.
3. These numbers may have leading zeros, which can be discarded (or alternatively, retained). Subtract $n′ − n″$ to produce the next number of the sequence.
4. Repeat step 2.
For example, if we start with $3524$ then we get:
$$5432 − 2345 = 3087$$ $$8730 − 378 = 8352$$ $$8532 − 2358 = 6174$$ $$7641 − 1467 = 6174$$
A few more points:
- The title refers to the convergence of the number as one of the exit conditions
- The riddle is written in like an algorithm, with the two indented lines representing a loop that is initialized with the line preceding it, and the exit criteria as the line that follows it
And a credit to Florian Bourse's answer for these points:
- Kaprekar's constant is 6174, and each line in the verse consists of words of length 6, 1, 7 and 4.
- The only numbers which when subject to Kaprekar's routine don't converge at 6174 are numbers composed of the same digit (e.g. 1111).
- This ties in to Bass's comment about the poker hand.
Building on Phylyp's answer :
All 4 digits numbers except quadruples lead to Kaprekar's constant 6174 when we apply the algorithm described.
Note that each line of the riddle shows words of respectively 6, 1, 7, and 4 letters, reminding us of the fix-point of the algorithm, which makes for the beauty of the riddle.