$$26\quad 28\quad 28\quad 30\quad 30\quad 28\quad 32\quad 30\quad ?\quad ?$$

If I consider the sequence of odd terms, then it follows increasing by $2$ each time. So the first missing term is $34$. Also if I consider the sequence of even terms then it oscillates, so the $2$nd missing term is $28$.

Am I correct? If I am, then I am looking for another beautiful logic.


closed as too broad by NL628, JonMark Perry, Gilles, Glorfindel, Rubio Mar 11 '18 at 11:15

Please edit the question to limit it to a specific problem with enough detail to identify an adequate answer. Avoid asking multiple distinct questions at once. See the How to Ask page for help clarifying this question. If this question can be reworded to fit the rules in the help center, please edit the question.

  • 1
    $\begingroup$ So you want us to find another possibility for this sequence? Shouldn't this be too broad? $\endgroup$ – NL628 Mar 11 '18 at 3:35
  • $\begingroup$ Yes, I want another possibility if my explanation is correct. $\endgroup$ – SAHEB PAL Mar 11 '18 at 3:36
  • 2
    $\begingroup$ To me, your explanation seems to be the clearest approach. I started mentally composing an answer after seeing the sequence until I read the exact same thing in your question! $\endgroup$ – Phylyp Mar 11 '18 at 4:18
  • $\begingroup$ Don't you mean the first missing term is $34$, since $32+2=34$? $\endgroup$ – boboquack Mar 11 '18 at 5:35
  • $\begingroup$ Yes.. I correct it. Thank you for mention it. $\endgroup$ – SAHEB PAL Mar 11 '18 at 5:46

It could be

+2 +0 +2 +0 -2 +4 -2 +4 -6 +8 -6 +8 ....

Which would make the next few terms

34 and 28

But then again, I can think of many many other possibilities, implying that this puzzle is way too broad.


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