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What is the smallest integer you can create using 1,2,3,4,5,6,7,8,9 that is strictly greater than 1?

  • You can use any mathematics symbol.
  • You must use all nine numbers.
  • You can't use the same number more than once.
  • You can't use the same mathematics symbol more than once.
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    $\begingroup$ "You can use any mathematics symbol" - you need to narrow this to a finite list. Otherwise I can just invent a mathematical symbol $*$ and define it almost however I want. There are a LOT of mathematical symbols out there. $\endgroup$ – Rand al'Thor Mar 8 '18 at 11:10
  • $\begingroup$ There's nothing wrong with the distinction "counting number" which refers to the natural numbers, i.e. positive integers. Here they are equivalent, since we only consider numbers greater than 1. I don't think there was any ambiguity in that part of the original statement. $\endgroup$ – Alex Jones Mar 8 '18 at 11:43
  • $\begingroup$ Adding to @votbear 's answer, if the smallest number we could make it not strictly greater than $1$, but still is greater nonetheless, then it would be as follows: $$\frac{1}{2\times 3\times 4\times 5\times 6\times 7\times 8\times 9} = \frac{1}{9!}$$ Through multiplication, it will be using $\times$ more than once, but we can write the denominator as $9!$ which is an alternative mathematical symbol that is only used once so.... $\endgroup$ – Mr Pie Mar 19 '18 at 10:10
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Uh...

The smallest integer which is strictly greater than 1 is 2, right?

Which is achievable by many means, one of which is

2 + (18 / 3 - 6) * [the rest of the numbers here]

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  • $\begingroup$ You can't use the same mathematics symbol more than once. How would you add the rest of the numbers ? $\endgroup$ – Doomenik Mar 8 '18 at 12:33
  • $\begingroup$ @Doomenik By concatenating the remaining numbers to 14579. That is if concatenating is allowed, otherwise this solution is invalid. $\endgroup$ – Rick van Osta Mar 8 '18 at 12:53

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