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Any mathematics symbols and processes to use the numbers 3, 5, 6, and 7 once each to get 100.

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closed as too broad by ffao, Alconja, Glorfindel, Rubio Feb 14 '18 at 22:46

Please edit the question to limit it to a specific problem with enough detail to identify an adequate answer. Avoid asking multiple distinct questions at once. See the How to Ask page for help clarifying this question. If this question can be reworded to fit the rules in the help center, please edit the question.

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$\sqrt{7^6}-3^5$ ...need more characters

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    $\begingroup$ Pretty! ...need more characters $\endgroup$ – Bass Feb 14 '18 at 19:18
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$100=(57+3)/.6$ if decimal point is allowed.

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7
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With the numbers in order:

$\frac{(3!)! - 5!}{6 \mod 7}$

EDIT: Added some "any processes" answers, some sillier than others:

$76 - 3 + 5 = 100$ (octal numerals)
$S(3*5*7-6)$ (successor function)
$$-\frac{\log\left[\left(\log\underbrace{\sqrt{\sqrt{\cdots\sqrt6}}}_{100}\right) / \log(3!)\right]}{\log{(7-5)}}$$ (generic method for obtaining any positive integer with 3,5,6 and 7, layout borrowed from ffao)

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$(3 + 7) ^ {\left\lceil \frac{6}{5} \right\rceil}$

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    $\begingroup$ no way, thought about getting 2 out of 6 and 5 forever, never thought of that $\endgroup$ – Guest Feb 14 '18 at 20:30
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If the "floor" function is acceptable:

$\left\lfloor 3\times5\times6.7 \right\rfloor$

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2
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$7!!-5×6/3!$ using double factorial

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35+67-2 $%The question doesn't say we can't use other digits$

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    $\begingroup$ Where did the 2 come from? $\endgroup$ – Catija Feb 14 '18 at 21:57
  • $\begingroup$ @Catija It's a "loophole" answer: the question doesn't say only those numbers. $\endgroup$ – Acccumulation Feb 14 '18 at 22:07
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${{6}\choose{3}} * 5 + \dot{7}$

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  • $\begingroup$ Could you explain a bit more what each step here means? I get that C(6,3) is combinations, but what's the apostrophe supposed to be? Is it a derivative? $\endgroup$ – DqwertyC Feb 14 '18 at 22:03
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    $\begingroup$ Yeah, that's it... Derivation of constant trick $\endgroup$ – Gabriel Omar Masi Feb 14 '18 at 22:11
  • $\begingroup$ I've updated it to use MathJax, if that's alright with you. $\endgroup$ – DqwertyC Feb 14 '18 at 22:23
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$$ \left \lceil 357 * \sin(-6) \right \rceil = 100$$

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