Not a date comes to your mind at first, but rather a specific date in time:

This date's human readable form is written as dd/mm/yyyy,
and when converted to a Unix Timestamp (epoch time), it's ddmmyyyy00.

  • dd is the two-digit day of the month
  • mm is the two-digit month month of the year
  • yyyy is the four-digit year

Note: a Unix Timestamp represents "the number of seconds that have elapsed since January 1, 1970 00:00 UTC" (Source).

This site might help: https://www.epochconverter.com/

Find such a date, if it exists. If it doesn't, please prove that it doesn't.

  • 6
    $\begingroup$ Should it be migrated to Flirting.SE ? $\endgroup$
    – Evargalo
    Commented Jan 16, 2018 at 16:24
  • 3
    $\begingroup$ I think he's wanting you to find a date that when in the format of dd/mm/yyyy, is equal to the unix timestamp that looks the same + two zeroes at the end. $\endgroup$
    – Sensoray
    Commented Jan 16, 2018 at 16:32

2 Answers 2


Is this what you're looking for?

0705199200 converts to dd/mm/yyyy 07/05/1992 (00:40)


The closest match I have found is


which has a timestamp of


which is only 2400 away from what it should be.

I used a small javascript program for it.

  var best = 1e9;
  for( var y=1970; y<2069; y++ ){
     for( var m=1; m<=12; m++ ){
        for( var d=1; d<=31; d++ ){
           var utc1 = Date.UTC(y,m-1,d)/1000;
           var utc2 = ((d*100+m)*10000+y)*100;
           var dif = Math.abs(utc1-utc2);
           if( dif<best ){
              best = dif;
              console.log(d+"/"+m+"/"+y+"  "+utc1+"  "+utc2);

You only have to search until 2069 because by then the first two digits exceed 31, so it can no longer represent a date.

  • $\begingroup$ I did my search the other way round, knowing that the yyyy part can be tuned easily. Because the hours and minutes are irrelevant, you'll see that you can actually get a Unix timestamp that matches with the readable format. $\endgroup$
    – slvrbld
    Commented Jan 16, 2018 at 16:46

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