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Last two corners are swapped

I've never met this postion before, and i'm starting to think it's an "illegal" one because i lend it to a friend before and he said he had to glue some fallen stickers. Am i missing an alorithm or do i have to disamble the cube?

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  • $\begingroup$ For clarity: Your picture implies it's only the two top corner pieces (as shown on the image) that are 'out of place', whilst the others are all looking fine? $\endgroup$ – Tim Couwelier Jan 3 '18 at 17:06
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Yes, this is impossible to do on a 5x5x5 using normal moves only (assuming only the two visibly wrong corner pieces are swapped and all the rest is solved).

An easy argument to see why: By ignoring slice 2 and 4 in every direction, slices 1, 3, and 5 essentially form a 3x3x3 cube. In your case those layers form a 3x3x3 with two corners swapped. It is well known that it impossible to swap two corners on a 3x3x3 cube without disturbing any other pieces. This is because every move is an even permutation of the pieces (4-cycle of edges combined with a 4-cycle of corners), whereas a single swap of corner is an odd permutation. Therefore some of the stickers of the corners or the middle edges must have been rearranged wrongly.

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  • $\begingroup$ How do you know no other pieces were disturbed? And what's your argument that it's impossible to disturb exactly two pieces? $\endgroup$ – Acccumulation Jan 2 '18 at 23:29
  • $\begingroup$ @Acccumulation Yes, it is possible to disturb only two pieces on a 3x3 because (by a converse argument) it is possible to solve a rubiks cube after disturbing two pieces. $\endgroup$ – NL628 Jan 3 '18 at 5:39
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It's impossible to prove that a position is valid merely by showing three faces, but showing three faces may sometimes be enough to prove that a position is invalid. This is one of those times. Knowing two sides of a corner piece is enough to infer the third, so it's possible to tell that the two top front pieces are swapped (the unseen face of the top front right corner is red) and that the far top left and bottom front left pieces are correctly positioned and oriented. Knowing the positions of three corners of a side, and seeing the side's color on a fourth piece, makes it possible to identify the other two colors of that piece. It is thus possible to infer from the picture that all three of the corner pieces that have exactly one side showing are correctly placed. Having accounted for the positions of seven corner pieces, it's possible to infer that the eighth must also be correctly placed. Consequently, the only way the stickers on the cube could be "correct" would be if it had been disassembled and the two top front corners swapped.

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  • $\begingroup$ It could still be that there are two edge pieces swapped. On a 3x3x3 and a 5x5x5 it is possible to swap two corners and two edges simultaneously. This is besides the point however, as I would assume the poster is not trying to mislead us, and they say that this is as far as they got while solving it, so it is a reasonable assumption that all the unseen pieces are already solved. $\endgroup$ – Jaap Scherphuis Jan 3 '18 at 16:24
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Meta answer:

If you're genuinely asking, you should show the other sides. If it were in a valid position, it would be impossible to know that from the picture. Which leads to the conclusion that if you already know whether it's a valid position and you're asking just as a puzzle, then the answer must be "no", because otherwise it would impossible to answer.

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  • $\begingroup$ Puzzling.SE is not for posting puzzles, but also for questions about puzzles. This is the latter, while you seem to imply only the first option goes. $\endgroup$ – Tim Couwelier Jan 3 '18 at 11:14
  • $\begingroup$ @TimCouwelier It took me a while to figure out what you are saying. Apparently because this is a question about a Rubik's cube, and Rubik's cube is a puzzle, you think this is a question about a puzzle. But it's not; the OP poses a puzzle in its own right as to whether this is a legal position. If the OP is legitimately asking, and not intending it to be a puzzle, then the choice to show only three sides makes no sense. I think I made that clear in my answer. It's not that I think that questions about puzzles in general "go", but rather this specific question simply makes no sense as such. $\endgroup$ – Acccumulation Jan 3 '18 at 16:04

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