3
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If-

ONE * THREE * FIVE = 225

NINE * SEVEN + TWELVE = X

225 + X = Y

10,18,32,56,93,146,?

? + Y = Z

Prove that, Z = 4561

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3
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ONE * THREE * FIVE = 225

$LHS$
$= ONE * THREE * FIVE$
$= (one*one)* (three*three)*(five*five)$
$= (1*1)*(3*3)*(5*5)$
$= 1*9*25$
$= 225$
$= RHS$

NINE * SEVEN + TWELVE = X

$X= NINE * SEVEN + TWELVE$
$= (nine*nine)*(seven*seven) + (twelve*twelve)$
$= (9*9)*(7*7) + (12*12)$
$= 81*49 + 144$
$= 3969 + 144$
$= 4113$

225 + X = Y

$Y= 225 + X = 225+4113 = 4338$

10,18,32,56,93,146,?

$ 10, 18, 32, 56, 93, 146, 223 [?=223]$
$f(x) = (2n^6 – 39n^5 + 290n^4 – 825n^3 +1688n^2 + 324n + 2160) /360$

? + Y = Z

$Z = ? + Y= 223+4338= 4561$

From this we can say that,

$Z = 4561$

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  • $\begingroup$ Hmf smarty pants... $\endgroup$ – iiRosie1 Dec 31 '17 at 14:20
  • $\begingroup$ So, in essence, invent a plausible solution for the first line, do random math to acquire an Y, figure out the required ’?’, and fit an arbitrary polynomial to that value. Cheeky. I like it. +1 $\endgroup$ – Bass Dec 31 '17 at 16:21

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