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I have this puzzle for adding 2 numbers (Or sequences)

Does anyone have an idea about how this addition works? $$ 5+1=9\\3+1=10\\5+2=21\\8+2=23\\9+0=28\\4+3=?? $$

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  • 8
    $\begingroup$ Care to tell us where this puzzle comes from? $\endgroup$ – Gareth McCaughan Nov 28 '17 at 22:34
  • $\begingroup$ in fact my friend send it to me $\endgroup$ – user11618 Nov 28 '17 at 22:56
  • $\begingroup$ may be $$ 4 + 3 = 31 $$ $\endgroup$ – Mandar Nov 29 '17 at 13:52
  • $\begingroup$ @Mozfox how is that ? $\endgroup$ – user11618 Nov 29 '17 at 22:16
4
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I think the answer can be

21

Reason

6=9 //5+1=9 
4=10 //3+1=10
7=21 //5+2=21
10=23 //8+2=23
9=28 //9+0=23
7=21 //4+3=21 as already given of 5+2=21
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  • $\begingroup$ For your second line, it's actually 3+1=10, not 3+2. $\endgroup$ – Lolgast Nov 30 '17 at 8:15
  • $\begingroup$ I don't think it's that easy $\endgroup$ – user11618 Nov 30 '17 at 11:19
  • $\begingroup$ @user11618 any hint $\endgroup$ – rudra Nov 30 '17 at 11:20
  • $\begingroup$ @rudra I don't know why I got downvoted :3 , but I don't think your answer is right $\endgroup$ – user11618 Nov 30 '17 at 19:01
  • $\begingroup$ @user11618 You are downvoted because this is completely random. And the formula submitted by you is not matching with the statement $\endgroup$ – rudra Dec 1 '17 at 1:56
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3+1 = 10 is what’s given. So

4 = 10

8+2 = 23. So 10 = 23.

5+2 = 21. So 7 = 21.

3 = 10-7 = 23 - 21 = 2

Therefore,

4+3 = 10+2 = 12


This seems quite improbable but well who knows?

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Thanks every body, I've found the solution.
$$ 5+2=21 \\ 5^2+2^5+(5+2)!=5097 \to 5+0+9+7 = 21\\ x+y = ?\\ x^y + y^x +(x+y)! = abcd \to s= a+b+c+d $$

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    $\begingroup$ First of all, this is completely random and so far-fetched that I don't believe it's actually solvable. $\endgroup$ – Levieux Nov 30 '17 at 13:02
  • $\begingroup$ Secondly, you've made a mistake: 5^1+1^5+(5+1)!=5+1+720=726 -> 15. Probably 120 was erroneously used instead of 720 by the creator of this puzzle... $\endgroup$ – Levieux Nov 30 '17 at 13:02
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Given the formula I get:

$$4 ^ 3 + 3 ^ 4 + (4 + 3)! = 5185$$
$$5 + 1 + 8 + 5 = 19$$

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