I'm looking for a TV series. A hint is hidden in the following image:

As this is a you might want to download the image.

  • 4
    $\begingroup$ Would a steganography tag be appropriate? $\endgroup$
    – Quintec
    Nov 20, 2017 at 1:14
  • 1
    $\begingroup$ This is a famous picture, but I can't find any instance of it on the web whose resolution as as high as in this picture -- yet it doesn't look like it was upsampled from a lower-resolution original. (Nor, for what it's worth, do I see obvious differences other than resolution between this and other copies of the image on the web. But I haven't looked all that hard.) $\endgroup$
    – Gareth McCaughan
    Nov 20, 2017 at 2:04

3 Answers 3


It looks like you're hiding:

South Park

Based on the fact that

Using this online steganography tool, the following image is hidden in the LSBs (cropped from the bottom left corner):

Sexual Harassment Panda

This is a picture of the South Park character, Sexual Harassment Panda


The answer is

Genius, the tv series.

The photograph is of

I found the photo on wikipedia's page for the 1911 Solvay Conference. The caption reads, "Photograph of the first conference in 1911 at the Hotel Metropole. Seated (L-R): W. Nernst, M. Brillouin, E. Solvay, H. Lorentz, E. Warburg, J. Perrin, W. Wien, M. Curie, and H. Poincaré. Standing (L-R): R. Goldschmidt, M. Planck, H. Rubens, A. Sommerfeld, F. Lindemann, M. de Broglie, M. Knudsen, F. Hasenöhrl, G. Hostelet, E. Herzen, J.H. Jeans, E. Rutherford, H. Kamerlingh Onnes, A. Einstein and P. Langevin."

It may only be coincidence but

Scientists Max Plank and Albert Einstein are both in the photo and are also portrayed in a few episodes of the tv series "Genius".

Note: Not sure if this answer really fits the enigmatic/computer puzzle tags so it might be another tv series that the OP is looking for.


The series is:


The reason is:

The image file is 3.14 MB in size. Pi (π), the mathematical constant, starts with 3.14.

  • $\begingroup$ I shspect the questioner could have got closer to pi if that was the case $\endgroup$
    – Jasen
    Nov 20, 2017 at 4:33

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