You are allowed to use the four standard operations (+-/*) to get 125, using each of the following digits exactly once: 2, 3, 4, 5, and 6.
I came up with an answer, but took me a while; curious to see what you all come up with!
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Sign up to join this communityYou are allowed to use the four standard operations (+-/*) to get 125, using each of the following digits exactly once: 2, 3, 4, 5, and 6.
I came up with an answer, but took me a while; curious to see what you all come up with!
In case brackets are not allowed
$2 + 3 + 4 * 5 * 6$
Here's an answer that I get:
$$6\times4\times(2+3) + 5=125$$
All earlier provided are disciplined answers. Here is an undisciplined one
(23 * 5) + 4 + 6, that is 115 + 10 = 125. This is undisciplined as it used concatenation of numbers.
Hope I'm not late (or wrong).
6*5*4+3+2
I think this one's different than the other answers:
$(6 * 5 + 2) * 4 - 3 = 32 * 4 - 3 = 128 - 3 = 125$
You can avoid brackets with reverse polish notation:
6 5 * 2 + 4 * 3 -