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You are allowed to use the four standard operations (+-/*) to get 125, using each of the following digits exactly once: 2, 3, 4, 5, and 6.

I came up with an answer, but took me a while; curious to see what you all come up with!

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    $\begingroup$ Until I saw that you could only use the basic operators, I had $5^{4\times 6\div 2^3}$ $\endgroup$ – GamrCorps Nov 18 '17 at 22:21
  • $\begingroup$ If there was a $1$, then I would have used $4^3 + 6\times 5\times 2 + 1$ $\endgroup$ – Mr Pie Nov 18 '17 at 23:12
  • $\begingroup$ Or, if we were also allowed to concatenate and use powers, then I would have done $(6 + 3)^2 + 4||5 - 1$ $\endgroup$ – Mr Pie Nov 18 '17 at 23:15
  • $\begingroup$ Or I could just be simple if there really was a $1$ and just do $2\times 3\times 4\times 5 + 6 - 1$ $\endgroup$ – Mr Pie Nov 18 '17 at 23:17
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In case brackets are not allowed

$2 + 3 + 4 * 5 * 6$

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  • $\begingroup$ Very nice - and I think you're probably right that brackets aren't allowed (in the original problem), so this is probably the best answer. $\endgroup$ – E. Villiger Nov 18 '17 at 19:47
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    $\begingroup$ not only no brackets, but in the order given, well done $\endgroup$ – Jasen Nov 18 '17 at 22:42
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Here's an answer that I get:

$$6\times4\times(2+3) + 5=125$$

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  • $\begingroup$ That's actually easier than the one I came up with :D $\endgroup$ – E. Villiger Nov 18 '17 at 19:11
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    $\begingroup$ How come you didn't notice you could exchange 2+3 and 5 to avoid parenthesis? ;) $\endgroup$ – Cœur Nov 19 '17 at 10:06
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$$(6\times4+3-2)\times5 = 125$$

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All earlier provided are disciplined answers. Here is an undisciplined one

(23 * 5) + 4 + 6, that is 115 + 10 = 125. This is undisciplined as it used concatenation of numbers.

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Hope I'm not late (or wrong).

6*5*4+3+2

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    $\begingroup$ Except for reversing the order, this is identical to the accepted answer, which was posted 18 hours earlier. $\endgroup$ – David Richerby Nov 19 '17 at 17:14
  • $\begingroup$ @DavidRicherby Sorry about that. I honestly didn't peek at the previous two answers that had been posted before mine. $\endgroup$ – MorrisIriga Nov 28 '17 at 11:47
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I think this one's different than the other answers:

$(6 * 5 + 2) * 4 - 3 = 32 * 4 - 3 = 128 - 3 = 125$

You can avoid brackets with reverse polish notation:

6 5 * 2 + 4 * 3 -

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