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I am learning to solve a 4x4x4 Rubik's cube and I think that the beginner OLL parity alg:

(r U2 x r U2 r' U2 l U2 r' U2 r U2 r' U2 r')

is a little too complex.

Does anyone know a simpler alg for it?

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I think this is the simplest: \begin{array} \ r\; U2\; x\; r\; U2\; r'\; U2\; l\; U2\; r'\; U2\; r\; U2\; r'\; U2\; r' \end{array}
Unless this works: \begin{array} \ r2\;F2\; U2\; r'\; F'\; u\; L'\; U2\; L\; u'\; F'\; r'\; U2\; r2\; F2\; r\ \end{array}

You can find all the 4x4x4 parity algorithms here : https://www.speedsolving.com/wiki/index.php/4x4x4_Parity_Algorithms

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  • $\begingroup$ see my reply to your response (specifically regarding information about the algorithm which you posted as being easy to remember). Of course, you are probably aware of the DP algorithm (that is just a 4 move sequence repeated 5 times) that I found two months after you posted this response (which I mention in my answer to this topic's question), so maybe you think that's easier than the one you listed. I'm obviously a little late in posting this, but better late than never! $\endgroup$ – Christopher Mowla Apr 4 at 22:15
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r' U2 l F2 l' F2 r2 U2 r U2 r' U2 F2 r2 F2

Super simple! (corrected version)

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  • $\begingroup$ Papa Crescendo’s YouTube channel has a great way to memorise this algorithm. $\endgroup$ – Damian Powell Jun 17 at 20:07
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(Rr)2 B2 U2 (Ll) U2 (Rr)' U2 (Rr) U2 F2 (Rr) F2 (Ll)' B2 (Rr)2

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  • $\begingroup$ Keep in mind that this is not a strict OLL parity alg, as it reorients two corners and permutes two corners and edges. $\endgroup$ – George A. Solodun Feb 16 at 2:27
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I am grateful that Redline provided a link to my wikipage!

And I have a story about the algorithm he thinks/thought was easy to remember. YES, it works. I found it along with many other algorithms by using Cube Explorer for the 3x3x3. Unlike many 4x4x4 OLL parity algorithms which people have gotten from 3x3x3 solvers, this one was not obvious to translate to the 4x4x4. As you can see, it has some very unusual turns; and it is very unique! See it on my wikipage for more details!

On that page, one can find a 4 move algorithm which needs to be repeated 5 times to fix double parity. But here is my original post about it on Reddit.

One of the algorithms in that list is Rw' (F2 U' Lw' U)5 Rw, for example.

For those who want a "pure verson" as George A. Solodun does, I actually derived the above double parity algorithm from an algorithm Floyd Newberry came up with for the "pure" edge flip case.

(Rw B' z')(2R' F U2 F')4 2R' (z B Rw')

If you don't know the notation of these algorithms, GREAT. That's fine. Just click the links and observe.

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