Move a number's position in order to get the right equation.
Can't tell if moving one digit is all we're are allowed, but this one is SOOO close:
62 is equivalent to 43+19. so we have 43+19-5+3x2=25. By moving the +19 to the RHS we are left with
43-5+3x2=25+19 ==> 43-5+6 = 44 ==>44=44
I began this approach by looking into re-writing the constants as quotients (as in 275/55=5, then move the numerator 275 above the 25 to get 11, but this equation eventually works out to 13=11...) I am aware that my final method is not as eloquent as my original attempt, but I think it warrants being a correct answer. (and possibly spark some new ideas outside of the box) Afterall, I don't think anyone would argue with (62 is equivalent to 43+19).
I think, following is right position.
25 - 6 + 3 x 2 = 25
Can you do:
62 - 5 + m * 2 = 25 (assuming I can move the position of 3 so its on its side and then count it as an m)
simplified is then:
57 + 2m = 25
2m = -32
m = -16
It's an equation. if its the right one is up to preference
Using the updated rule that you move an attached operator with the digit you can just move the
to the other side to get
62-5+3=25x2 ... (both sides now equal 50)