Colour in all cells in the top horizontal row in Red, the second in Blue, then Green, Red, Blue and so on.
R R R R R R
B B B B B B B
G G G G G G G G
R R R R R R R R R
B B B B B B B B B B
G G G G G G G G G G G
R R R R R R R R R R
B B B B B B B B B
G G G G G G G G
R R R R R R R
B B B B B B
Thanks to Mike Earnest for the diagram!
As you place tiles on the board, denote the number of each colour remaining uncovered at any stage as R, G, B.
Each piece must either cover 3 cells of a single colour, or one of each. Either way, the relative numbers of each colour modulo 3 remains unaltered, i.e. (R-G)%3, (G-B)%3 and (B-R)%3 are constant.
Initially there are 6+9+10+7=32 reds (=2 mod 3), and the same number of blue. There are 8+11+8=27 greens (=0 mod 3). So R=B mod 3 and G=R+1 mod 3.
Once there is only one cell left uncovered, that cell must therefore be Green. So it must be on row 3, 6 or 9.
By rotating through 60 degrees in either direction and applying the same logic, the uncovered cell must be one of the seven highlighted in the other answers - either the central cell or 3 rows in from any two adjoining edges.