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Is there an faster algorithm to rotate 2 opposite corners? I can't find anything else but doing the sexy move multiple times.

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    $\begingroup$ "The sexy move"? Is that an actual cube-solving move? $\endgroup$ – F1Krazy Jul 13 '17 at 13:23
  • $\begingroup$ What do you mean by opposite - diagonally opposite in the same face, or on opposite sides of the cube (not sharing a face)? $\endgroup$ – Jaap Scherphuis Jul 13 '17 at 13:53
  • $\begingroup$ @F1Krazy R U R' U' or some rotation/symmetry of that move. Surprisingly useful and really quick to perform. $\endgroup$ – James Coyle Jul 15 '17 at 18:43
  • $\begingroup$ @F1Krazy Yes. $\endgroup$ – Rand al'Thor Jul 16 '17 at 12:17
  • $\begingroup$ I mean on a diagonal, so not sharing any faces. $\endgroup$ – Cristiano Marchettini Jul 19 '17 at 15:51
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This algorithm can be adapted to do what you need.

F D' F' B F D' F' U' F D F' D' F D F' U

Notation is standard

To deal with non adjacent corners where one corner is on the right hand side of F (corners in a diagonal), rotate U twice instead of once in the algorithm i.e. F D' F' D F D' F' U2 F D F' D' F D F' U2 If both corners are far opposites (do not share any faces), make sure one corner is on the right hand side of F (as before), rotate L2 and then apply the original algorithm, and rotate L2 to finish.

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    $\begingroup$ What is T? I haven't seen that notation before. $\endgroup$ – Kruga Jul 14 '17 at 7:30
  • $\begingroup$ This would rotate 2 corners sharing the same face, I'm looking for something where the 2 corners are on a diagonal $\endgroup$ – Cristiano Marchettini Jul 19 '17 at 15:52
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Twist two diagonally opposite corners. One is twisted clockwise while the other anti-clockwise.

U L U' R2 U L' U' R2 D L2 D' R2 D L2 D' R2

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This rotates front right clockwise and back left counterclockwise:

(R'D2R B'U2B)X2

You can rotate the cube to avoid having to turn the back side but this orientation has the handy "hardy har, bub" mnemonic.

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