4
$\begingroup$

This puzzle asked me to in the interview.

In a Cricket match, Two batsmen are on 92(on strike) and 99 runs respectively. Three balls remaining and both batsmen make 100 and win the match.

Note:

  • No extra ball or run allowed(wide, no ball, over throw etc).
  • Last wicket on crease.
  • both batsmen need complete 100. No more than 100 run.

How is it possible?

$\endgroup$
  • $\begingroup$ It's so easy. Batsmen on strike hit SIX (1st Ball), 2nd ball 2 runs + 1 overthrow (Now Batmen on strike finish 100 and reached at Non-strike end), then Batsmen 2 came on strike hit 1 run in 3rd ball (complete 100) $\endgroup$ – CR241 Jul 13 '17 at 16:48
  • $\begingroup$ No over throw run allowed $\endgroup$ – James Jul 13 '17 at 16:55
  • $\begingroup$ Yeah That's what I mention in above comment, in 2 balls (6+2) 8 for Batsmen-1 can reach 100. But after ball 2, Batsmen-1 on non strike because of Overthrow and final ball Batsmen-2 came on strike and hit 1 run (complete 100) $\endgroup$ – CR241 Jul 13 '17 at 17:02
  • $\begingroup$ Were you interviewing for a cricket commentary position? $\endgroup$ – Peter Taylor Jul 14 '17 at 6:39
3
$\begingroup$

So far as I am aware,

it is not illegal or impossible for a batsman to score any number of runs while waiting for the fielders to get their act together; it's just very unusual for the number to be large.

So, e.g., perhaps

batsman 1 scores 7, leaving batsman 2 facing the bowler;
batsman 2 scores 1, leaving batsman 1 facing the bowler;
batsman 1 scores 1.

Of course

we can redistribute batsman 1's runs, provided the first number is odd; perhaps 3+4 is more realistic.

$\endgroup$
2
$\begingroup$

1st ball:

Striker batsman(92) hits the ball for 3 run but when he runs he made 1 run short and fielder throw the ball. By this he got 2 run(who reached on 94) and reached at non-striker's end.

2nd ball:

Non-striker batsman reached at striker's end and he made 1 run and completed his 100 and reached at non-striker's end.

3rd ball:

The Non-Stricker batsman reached at the striker's end and he hits six off the last ball and completed his 100.

$\endgroup$
  • 4
    $\begingroup$ Um.. you self-answered far too soon IMO. Only 50 views so far. $\endgroup$ – Sid Jul 13 '17 at 12:24
  • $\begingroup$ @Sid Then, Can I delete my answer? $\endgroup$ – James Jul 13 '17 at 13:31
  • $\begingroup$ This answer is more complicated than mine; what is its advantage over mine? (E.g., does mine not work for some subtle reason?) $\endgroup$ – Gareth McCaughan Jul 13 '17 at 17:58
2
$\begingroup$

As an alternative to running five (or seven) - a fielder has brought a helmet on to the pitch and for the time being has taken it off and left it behind the wicket-keeper's position. On the first ball, the ball strikes the helmet on the way to the boundary. This scores an automatic 5. The batsman on strike then makes three on the next ball, leaving the other batsman at the right end to score a single on the last ball.

$\endgroup$
0
$\begingroup$

I think

Batsman 1 - Takes 1 run scores 100.
Batman 2 hits the ball - They both run between crease to gain 4 runs. A fielder throws the ball at the wickets but it misses and reaches the boundary to give 4 more runs. That's it. No extras. Done! Overthrow runs are not extra runs.

$\endgroup$
  • $\begingroup$ The batsman on 92 receives the first ball. $\endgroup$ – Rupert Morrish Dec 9 '18 at 20:10

Your Answer

By clicking “Post Your Answer”, you agree to our terms of service, privacy policy and cookie policy

Not the answer you're looking for? Browse other questions tagged or ask your own question.