This not-so-simple puzzle asked by my teacher today, given:
2 + 2 = 3
4 + 8 = 27
3 + 4 = 8
So, the answer for:
5 + 32 = ?
I'm new here so pardon my mistakes. Please let me know what you guys thinks about this riddle.
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Sign up to join this communityThis not-so-simple puzzle asked by my teacher today, given:
2 + 2 = 3
4 + 8 = 27
3 + 4 = 8
So, the answer for:
5 + 32 = ?
I'm new here so pardon my mistakes. Please let me know what you guys thinks about this riddle.
Rearranging the statements:
$2+2=3$
$3+4=8$
$4+8=27$
We see a pattern develop:
$(n+1) + 2^n = x$
If the first equation resulted in $1$, then $x = n^3$ is a solution. If the second equation resulted in $9$, then $x = 3^n$ is a solution. Alas, neither of these is the case.
Additionally, the final request pairs $5$ with $32$, which would have ordinarily been paired with $16$ if following the suggested pattern.
Let each equation be represented as $a+b=c$
I observed that in the first equation $a * (b - 1)$ gives us $2 * 1 = 2$,
and in the second it gives us $4 * 7 = 28$,
and finally in the third it gives us $3 * 3 = 9$.
These numbers all differ from their respective answers by 1, and I thought that could be represented by adding a term to the above multiple, $(-1) ^ x$ where $x$ represents the boolean value of $a < b$.
Using this logic, $5 + 32$ would equal $5 * 31 + (-1) ^ 1 = 154$.
One convoluted potential answer:
$2+2=3$
$4+8=27$
$3+4=8$
Step one: Express teach term as its most reduced exponential
$2^1 + 2^1 = 3^1$
$2^2 + 2^3 = 3^3$
$3^1 + 2^2 = 2^3$
Step two: Multiply instead of exponentiate
$2*1 + 2*1 = 3*1$
$2*2 + 2*3 = 3*3$
$3*1 + 2*2 = 2*3$
or
$2+2=3$
$4+6=9$
$3+4=6$
Step 3: Note the left side is always 1 greater than the right
SO:
5 + 32= 49
because
$5^1 + 2^5 =(7^2) + 1$
$5*1 + 2*5 =(7*2) + 1$
$5+10=(14) + 1$
My answer to $5+32$ is $135$
Reasoning:
The given numbers can be written as follows:
$2*2^1-1^2=3$
$3*2^2-2^2=8$
$4*2^3-3^2=27$
$5*2^5-5^2=135$