2 6 4 9 1 5 9 9 7
The word/group of words is __________?
Everyone is familiar with this (I guess).
Hint 1
The numbers are (somehow) associated with the position of the letters in the English alphabet.
Hint 2
M = 4
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5
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$\begingroup$ Could be I M A G I N A T I O N? $\endgroup$– AnuragJul 6, 2017 at 9:23
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$\begingroup$ :( nopeeeee !!! wait i'll add a hint! $\endgroup$– starkgurlJul 6, 2017 at 9:27
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$\begingroup$ 11 letters, but only 9 numbers. Is that intentional? $\endgroup$– GlorfindelJul 6, 2017 at 9:31
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$\begingroup$ @Glorfindel yep yep yep!!! $\endgroup$– starkgurlJul 6, 2017 at 9:33
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$\begingroup$ I've a feeling it's related to the normal phone numpad..but even if i'm correct it'll be hard to guess, seeing everyone might have a different childhood :) $\endgroup$– AlexJul 6, 2017 at 16:14
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2 Answers
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2
If you associate the numbers 1 to 9 with the alphabet, like below
$\array{~1&~2&~3&~4&~5&~6&~7&~8&~9\\A&B&C&D&E&F&G&H&I\\J&K&L&M&N&O&P&Q&R\\S&T&U&V&W&X&Y&Z&\&}$
then the numbers, with a little choice, give
“Tom & Jerry”, and these two names give the 11 letter classic cartoon, Tom and Jerry.
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$\begingroup$ Haha You got the answer! well done! my reasoning is just a another form of your reasoning! but still its absolutely correct!!!!! $\endgroup$ Jul 9, 2017 at 5:36
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2$\begingroup$ oh i almost forgot!!! '&' (ampersand) is the 27th letter of the alphabet!! $\endgroup$ Jul 10, 2017 at 1:33
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4
This is perhaps going to be "too broad".
One possible answer -
Substitution code, where:
1 = B
2 = N
4 = S
5 = L
6 = O
7 = D
9 = E
which gives:
2 6 4 9 1 5 9 9 7
N O S E B L E E D
a childhood experience, very common for some, everyone is familiar with (I guess).
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$\begingroup$ :( nope that isnt the answer but well tried! i'll give you a vote :) $\endgroup$ Jul 6, 2017 at 8:13
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4$\begingroup$ (@starkgurl - Other than it not being the answer in your head, there's no particularly apparent reason in the puzzle to indicate it's wrong.- hence, "too broad". You may want to add something to give the puzzle a clearer path to a solution, or more clearly defined boundaries.) $\endgroup$– Rubio ♦Jul 6, 2017 at 8:15
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$\begingroup$ It is wrong, im sorry to say. Please read all the clues in the question before commenting :) thanks $\endgroup$ Jul 6, 2017 at 8:21
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1$\begingroup$ I think it's supposed to be an 11 letter word somehow - also you have 0 - E not 9 - E. $\endgroup$– n_plumJul 6, 2017 at 12:25