The complete conditions for this scrambled cube can be described alternatively as the following:

  • 1. Each face has less than 3 squares of the same color, which leads to

  • 1a. Each face has 5 or 6 different colors.

  • (2. It's a huge bonus if the same-color squares are not adjacent to each other. In other words, they don't share an edge.

  • 2a. It's even better if they don't share a vertex!)

Please provide pictures or sequence algorithms.


1 Answer 1


Yes it is possible!

Do you know how to get it into a checkered state? Looking at any face you then do as follows....

Keep the same face towards you the entire time.

  1. Turn left side clock-wise
  2. Turn right side clock-wise
  3. Turn top side clock-wise
  4. Turn bottom side clock-wise
  5. Turn left side clock-wise

enter image description here enter image description here

There are a couple colors that are sharing edges but there are no more then 2 of the same color per side

I had some more time to mess around with it and have the answer for Q2 but not Q2a. There is only one difference

The last step.. Instead of doing Left side clock-wise do left side counter clock-wise

enter image description here enter image description here

  • $\begingroup$ Checkered meaning this i.ytimg.com/vi/yzEv4aQBb7I/hqdefault.jpg $\endgroup$
    – Saloaty
    Jun 29, 2017 at 20:33
  • $\begingroup$ Thank you! For now conditions 1 & 1a are fulfilled. Can you or anyone solve condition 2? My uneducated guess is that condition 2a is even several times tougher than 2! $\endgroup$
    – 12tn2
    Jun 30, 2017 at 8:02
  • 1
    $\begingroup$ Yes! I've found the steps from a solved cube as: D R' L' U D R2 L2 F2 B2. Now we only have the obstacle of 2a left ;) $\endgroup$
    – 12tn2
    Jul 1, 2017 at 3:00
  • $\begingroup$ Oh nice! That one will for sure will be more difficult. $\endgroup$
    – Saloaty
    Jul 1, 2017 at 3:08

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