# Complete the equality (medium-hard)

1. Complete the equality to make it true:

1 1 1 1 1 = 945

2. Using similar logic, solve for this:

1 1 1 1 1 = 80

Info:

• You should modify only the left side of =
• The equation must remain an equality.
• You can use any operator you want, as many parentheses as you like, combinations, decimals, powers and roots of any value etc.
• There is at least 1 guaranteed solution for each

Be creative :)

• combining 1s is possible, such as 11+111? – Oray Jun 17 '17 at 13:09
• yes, it is, if you'd like that – jack Jun 17 '17 at 14:35

# 1. 945

$(1+(1+1+1)!)!!\div.\bar{1}=945$, where $!!$ denotes double factorial. [Calculation]

# 2. 80

$((1+1+1\times 1)!)!\times .\bar{1}=80$. [Calculation]

• you got the idea. Now try without using the dash (vinculum) :D – jack Jun 17 '17 at 14:42

$((1+1+1+1)!! + 1)!! = 945$
$((1+1+1)! + 1 + 1)!!! = 80$, where 8!!! = 8 x 5 x 2