$A\tfrac{B}{C}=100$ is the equality where A,B,C are numbers generated by combining all digit values $0,1,2,3,4,5,6,7,8,9$ only once for each digit in total. For example;
$123\tfrac{4567}{890}$ is an example for A,B,C where $A=123$, $B=4567$, $C=890$.
is an example to assign unique digits only A,B,C values.
So how many possible different A,B,C values are there to make this equality true?
Example: If this question was asked without using $0$ digit, one of the answers would be;
$91\tfrac{5742}{638}=100$
Note: $01234$ and other numbers starting with $0$ cannot be accepted as a number since it is not valid 5 digit number.
Clarification: $A\tfrac{B}{C}$ is a mixed number meaning it is also equal to $A+\frac{B}{C}$.