# Polyomino T hexomino and rectangle packing into rectangle

Let's pack some (one or more) T hexominoes together with some (one or more) small $a\times b$ rectangles into some bigger $m\times n$ rectangle without holes and overlapping pieces.

For example, I can pack two T hexominoes and eight $1\times1$ rectangles into a $5\times4$ rectangle: Find as many as you can different integer pairs $\{a,b\}$ so that one or more rectangles of size $a\times b$ can be packed together with T hexominoes into a $m\times n$ rectangle without holes and overlapping pieces.

Provide images of solutions if you claim that some combination is possible. Please, put your images in spoiler tags so that other users can try find themselves.

If some answers will have same number of pairs $\{a,b\}$, then answer with smaller total area of outer rectangles on example images is preferable. If area also equal, then earlier posted answer is preferable.

EDIT: Please, add to your answers total area of outer rectangles. If one tiling implicitly includes several $a\times b$ rectangles, then multiply area by number of combinations it includes.

### Notes

I can guarantee that there exist solutions following integer pairs:
$1\times1$, $1\times2$, $1\times3$, $1\times4$, $1\times5$, $1\times6$, $1\times8$, $1\times9$,
$2\times2$, $2\times3$, $2\times4$, $2\times5$, $2\times6$

I'm wondering why a $1\times7$ rectangle solution is hard to find (maybe it's impossible?) when there exist solutions for with $1\times8$ and $1\times9$ rectangles.

1 week after posting, I'll put up my own answers for unfound combinations.

• Please clarify your question; I can't understand what you're asking. Do you want to pack $m$ T-hexominoes and $n$ $a\times b$ rectangles into a $c\times d$ rectangle? What are the combinations you're looking for of $m$, $n$, $a$, $b$, $c$, $d$? Are some of these fixed? Nov 19, 2014 at 21:56
• Thanks for editing! But when you say 'a 1x7 rectangle solution', does this mean $a$ and $b$ are 1 and 7? What are the other parameters? Or are you just trying to pack some T-hexominoes and some 1x7 rectangles into a big rectangle of some size? Nov 19, 2014 at 22:05
• @randal'thor Yes, I'm "just trying to pack some T-hexominoes and some 1x7 rectangles into a big rectangle of some size". 1x7 is one that I'm suspicious about. Nov 19, 2014 at 22:09
• Under notes, you say $1 \times 7$ is impossible, then again that it is possible. Is the second supposed to be $1 \times 8$? In the list you have found, is the first $1 \times 2$ supposed to be $1 \times 1$? Nov 19, 2014 at 22:41
• The more solutions I see, the more I like this question. A pity I can not up-vote it more than I have already! I'm eager to the see the link to your homepage once it is up! Dec 14, 2014 at 17:48

2x2 - area 108 - optimal 2x3 - area 72 - optimal   2x4 - area 108 - optimal 3x4 - area 84 - optimal 1x5 - area 54 - optimal 2x5 - area 304 - optimal 3x5 - area 576 - optimal 2x6 - area 240 - optimal 1x7 - area 1034 1x8 - area 432 - optimal 3x8 - area 5880 1x9 - area 585 - optimal Note that by subdividing the yellow rectangles:
2x3 indirectly solves 1x1, 1x2, 1x3
2x4 indirectly solves 1x4 and 2x2
2x5 indirectly solves 1x5
2x6 indirectly solves 1x6

• Yes, it was a nice surprise. Nov 22, 2014 at 22:10
• Your 2x2 solution can be extended also for 2x4 - it'll be smaller then. Nov 24, 2014 at 10:28
• I know. I already did the picture and edited the answer. I must have forgotten to save the edits. I'll do that tonight. Nov 24, 2014 at 11:12
• No more rectangles found? I have some unfinished in my answer. Maybe they will help you. Seems like you have skill in finding tilings. Nov 26, 2014 at 18:38
• No more. I filled a number of pages with T patterns but managed only to improve on existing answers. Nov 26, 2014 at 22:50

1x1 1x2 1x3 1x4 1x6 These ones took me a while.

1x5 2x3 • Just curious, what interface/software are you guys using to make the graphs?
– Leo
Nov 21, 2014 at 19:08
• @Leo, I wrote a small image rendering application using Python and the Pillow library. I don't know what everyone else is using. Nov 21, 2014 at 20:12
• @Leo I wrote VB.NET application for creating polyomino tilings. In my opinion, fastest method without any special programs is to use PowerPoint - create figures from squares, group them and then it's easy to copy/move/rotate them. Nov 21, 2014 at 22:20
• Your 1x5 could be reduced to a 9 by 6 rectangle. Nov 22, 2014 at 14:35

Rev 4 - added 1 x 9 incorrect but still trying, added 1 x 5 using Florian's clue
Rev 3 - added 1 x 8 solution
Rev 2 - added 2 x 6 solution
Rev 1 - added 2 x 2 solution
Thanks for the clarification, Somnium. I will put some more answers here.

1 x 5 solution using Florian's clue (area = 54) 1 x 8 solution (area = 560) 1 x 9 incorrect still trying 2 x 2 solution (area = 144) 2 x 3 alternate (area = 72) 2 x 6 solution (area = 240) • BTW, your 2x3 is smallest possible. Nov 20, 2014 at 22:56

2x6 - area 240 Another solution 3x5 - area 1014 Following maybe will help someone.

2x9 unsuccessful try 1x7 unsuccessful try • Interesting sparse solution for 3x5. Dec 14, 2014 at 20:39

I found one for a new size, $4 \times 5$:

• That was unexpected! It's found by program or by hand? Jun 9, 2018 at 8:54
• By program. I'm getting better at hand-solving, but this is out of my league. Jun 9, 2018 at 9:12
• I usually try at first hand-solving, to see if there's some pattern, if there's something that can prevent solution existence, then do computer search. Do you have solutions of other size (may be bigger)? If I want to post your solution on my webpage (not so soon), do you want attribution? Jun 9, 2018 at 9:48
• It's not so much that I want attribution; because this content is posted on Stack Exchange, under the CC BY-SA 3.0 license you have to provide attribution; see the Terms of Service. (The flip side of this is that you don't even need to ask me for permission to publish the content elsewhere, though I appreciate it!) I don't have any more solutions at the moment, by the way. Jun 9, 2018 at 15:12
• @Somnium and as for something preventing solution existence, my program is far better than me at that as well. It takes half a second to realize that there's no solution for the F-pentomino + the 2x2 rectangle (well, at least not one with dimensions below 63x128). Jun 9, 2018 at 15:28