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This question is inspired by this one. You and your opponent play Russian roulette with two bullets. Quoting from the linked question:

You are challenged to a game of Russian roulette. Your opponent places two bullets side by side in a six chamber revolver and spins the chamber. She explains that the game is single turn-based. She then offers that you can choose who goes first.

However, since you are more motivated by survival than by fair play, both players would shoot their opponent instead of themselves if that increased their probability of surviving. To try to prevent this, a knife is placed in the table, so that if a player tries to shoot the other one and the gun doesn't fire, the other player will certainly kill him with the knife.

What's your probability of surviving the game if both players follow an optimal strategy?

Note: "Strategy" means choosing to play first or second and deciding in which turn to shoot the other player instead of their own head. Any other way of cheating is supposed to be prevented by other means.

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πŸ˜₯ πŸ…°πŸ…±πŸ…°πŸ…±πŸ…°πŸ…±

1/6 ⚫⚫βšͺβšͺβšͺβšͺ
1/6 βšͺ⚫⚫βšͺβšͺβšͺ
1/6 βšͺβšͺ⚫⚫βšͺβšͺ
1/6 βšͺβšͺβšͺ⚫⚫βšͺ
1/6 βšͺβšͺβšͺβšͺ⚫⚫
1/6 ⚫βšͺβšͺβšͺβšͺ⚫

πŸ…°πŸ”«
◻️ πŸ’₯βž‘οΈπŸ…°βš°οΈ
◻️ βŒβž‘οΈπŸ”„
πŸ…°πŸ”«πŸ…±
◻️ πŸ’₯βž‘οΈπŸ…°βš°οΈ
◻️ βŒβž‘οΈπŸ…°πŸ”ͺπŸ…±βž‘οΈπŸ…±βš°οΈ

βŒβŒβŒβŒβ” (πŸ…°)
1/1 βšͺβšͺβšͺβšͺ⚫⚫

πŸ…°πŸ”«
◻️ 1/1 πŸ’₯βž‘οΈπŸ…°βš°οΈ
πŸ…±πŸ”«πŸ…°
◻️ 1/1 πŸ’₯βž‘οΈπŸ…±βš°οΈ

βœ”οΈπŸ…±πŸ”«πŸ…°βž‘οΈπŸ’―πŸ…±βš°οΈ

βŒβŒβŒβ” (πŸ…±)
1/2 βšͺβšͺβšͺ⚫⚫βšͺ
1/2 βšͺβšͺβšͺβšͺ⚫⚫

πŸ…±πŸ”«
◻️ 1/2 πŸ’₯βž‘οΈπŸ…±βš°οΈ
◻️ 1/2 βŒβž‘οΈπŸ’―πŸ…±βš°οΈ
πŸ…°πŸ”«πŸ…±
◻️ 1/2 πŸ’₯βž‘οΈπŸ…°βš°οΈ
◻️ 1/2 βŒβž‘οΈπŸ…°πŸ”ͺπŸ…±βž‘οΈπŸ…±βš°οΈ

βœ”οΈπŸ…°πŸ”«πŸ…±βž‘οΈ1/2πŸ…°βš°οΈβž•1/2πŸ…±βš°οΈ

βŒβŒβ” (πŸ…°)
1/3 βšͺβšͺ⚫⚫βšͺβšͺ
1/3 βšͺβšͺβšͺ⚫⚫βšͺ
1/3 βšͺβšͺβšͺβšͺ⚫⚫

πŸ…°πŸ”«
◻️ 1/3 πŸ’₯βž‘οΈπŸ…°βš°οΈ
◻️ 2/3 ❌➑️1/2πŸ…°βš°οΈβž•1/2πŸ…±βš°οΈ
πŸ…±πŸ”«πŸ…°
◻️ 1/3 πŸ’₯βž‘οΈπŸ…±βš°οΈ
◻️ 2/3 βŒβž‘οΈπŸ…±πŸ”ͺπŸ…°βž‘οΈπŸ…°βš°οΈ

βœ”οΈπŸ…°πŸ”«/πŸ…±πŸ”«πŸ…°βž‘οΈ2/3πŸ…°βš°οΈβž•1/3πŸ…±βš°οΈ

βŒβ” (πŸ…±)
1/4 βšͺ⚫⚫βšͺβšͺβšͺ
1/4 βšͺβšͺ⚫⚫βšͺβšͺ
1/4 βšͺβšͺβšͺ⚫⚫βšͺ
1/4 βšͺβšͺβšͺβšͺ⚫⚫

πŸ…±πŸ”«
◻️ 1/4 πŸ’₯βž‘οΈπŸ…±βš°οΈ
◻️ 3/4 ❌➑️2/3πŸ…°βš°οΈβž•1/3πŸ…±βš°οΈ
πŸ…°πŸ”«πŸ…±
◻️ 1/4 πŸ’₯βž‘οΈπŸ…°βš°οΈ
◻️ 3/4 βŒβž‘οΈπŸ…°πŸ”ͺπŸ…±βž‘οΈπŸ…±βš°οΈ

βœ”οΈπŸ…±πŸ”«βž‘οΈ1/2πŸ…°βš°οΈβž•1/2πŸ…±βš°οΈ

❔ (πŸ…°)
1/6 ⚫⚫βšͺβšͺβšͺβšͺ
1/6 βšͺ⚫⚫βšͺβšͺβšͺ
1/6 βšͺβšͺ⚫⚫βšͺβšͺ
1/6 βšͺβšͺβšͺ⚫⚫βšͺ
1/6 βšͺβšͺβšͺβšͺ⚫⚫
1/6 ⚫βšͺβšͺβšͺβšͺ⚫

πŸ…°πŸ”«
◻️ 1/3 πŸ’₯βž‘οΈπŸ…°βš°οΈ
◻️ 2/3 ❌➑️1/2πŸ…°βš°οΈβž•1/2πŸ…±βš°οΈ
πŸ…±πŸ”«πŸ…°
◻️ 1/3 πŸ’₯βž‘οΈπŸ…±βš°οΈ
◻️ 2/3 βŒβž‘οΈπŸ…±πŸ”ͺπŸ…°βž‘οΈπŸ…°βš°οΈ

βœ”οΈπŸ…°πŸ”«/πŸ…±πŸ”«πŸ…°βž‘οΈ2/3πŸ…°βš°οΈβž•1/3πŸ…±βš°οΈ

❌2/3πŸ…°βš°οΈ
βœ”οΈ1/3πŸ…±βš°οΈ

I'll call the player who goes first A and the one who goes second B.

On the fifth turn it's A's move. If the game reaches this point, A knows that a round is chambered, so he will always opt to shoot B.

On the fourth turn it's B's move. At this point the odds that a round is chambered is 1:1 even. B knows if he fires at himself he will either die now or in the next round, so he opts to fire at A, where his odds of survival are 1:1 even.

On the third turn it's A's move. At this point the odds that a round is chambered is 2:1 against. It makes no difference what A does: if he fires at himself he dies now with probability 1/3, or dies in the next round with probability 1/2, leading to an odds of survival of 2:1 against. If he fires at B his odds are the same, 2:1 against.

On the second turn it's B's move. At this point the odds that a round is chambered is 3:1 against. If B fires at himself he dies now with probability 1/4, or dies in a subsequent round with probability 1/3, leading to an odds of survival of 1:1 even. If he fires at A his odds are 3:1 against, so he chooses to fire at himself.

On the first turn it's A's move. At this point the odds that a round is chambered is 2:1 against. It makes no difference what A does: if he fires at himself he dies now with probability 1/3, or dies in a subsequent round with probability 1/2, leading to an odds of survival of 2:1 against. If he fires at B his odds are the same, 2:1 against.

Thus B has the higher chance of survival, with odds of 2:1 on.

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  • $\begingroup$ If the last lines are probability of death for first and second player, I agree with your results. However, I can't follow your reasoning. Are those signs standard for the site? Is there a guide to read them? I might be missing some meaning, and I would like to understand the answer before accepting it. $\endgroup$ – Pere May 21 '17 at 22:15
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    $\begingroup$ @Pere You're not missing any standards or conventions, I was just having a little fun. I might add a written description later. $\endgroup$ – 2012rcampion May 22 '17 at 1:30
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    $\begingroup$ this actually could have been a reverse puzzling thing if you had posted it as a puzzle and also this puzzle was not posted. you should consider making a similar answer to a question, and the puzzle is what the original question/puzzle is. $\endgroup$ – Destructible Lemon May 22 '17 at 3:29
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    $\begingroup$ $\color{green}{\bf{\rlap{β—―}\ β–²}}\ $ πŸ‘ πŸ˜„ $\endgroup$ – Rubio♦ May 22 '17 at 4:24

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