3
$\begingroup$

Rubic's cube 4x4x4

I have only two sides that are not right but the other two are right... everything but that has done. How do I complete this 4x4x4 Rubik's cube?

$\endgroup$
  • $\begingroup$ puzzling.stackexchange.com/questions/413/… $\endgroup$ – n_plum Apr 19 '17 at 16:46
  • $\begingroup$ Can you show us the other sides so we know which face has which colour? $\endgroup$ – Beastly Gerbil Apr 19 '17 at 16:46
  • $\begingroup$ If you're saying everything is right apart from those two corner cubelets, I don't believe you. The near-top-right one has to go in the green/white/red corner, and the near-top-left corner (the other one that we can see is wrong) is green/yellow/something. I expect red is opposite orange and white is opposite yellow, and the near-bottom-left corner is also wrong. So you need a move to cycle three corners, not two. $\endgroup$ – Gareth McCaughan Apr 19 '17 at 16:48
  • $\begingroup$ I bet you can adapt a three-corner cycle from the 3x3x3 cube to do the equivalent job on the 4x4x4. $\endgroup$ – Gareth McCaughan Apr 19 '17 at 16:49
  • $\begingroup$ @BeastlyGerbil It looks like a standard cube, so white should be opposite yellow, blue opposite green and red opposite orange. $\endgroup$ – dcfyj Apr 19 '17 at 16:51
6
$\begingroup$

I replicated your case on my 4x4x4: enter image description here

This is an adjacent corner PLL parity case which can happen on even-layered cubes (like this 4x4x4, 6x6x6, 8x8x8, etc.)
Put green at the top and the two incorrect corners at the top-front (as in the picture above), and use the following algorithm (Here is an animation for this algorithm):

(Uu)2 (Ll)2 U2 l2 U2 (Ll)2 (Uu)2 F' U' F U F R' F2 U F U F' U' F R

where a capital letter is the outer later, and a lowercase letter is the inner layer (i.e. Uu is the top two layers; l is the inner left slide; etc.)

Source including all 4x4x4 parity cases.


Why do parities happen on a 4x4x4 which aren't possible on a 3x3x3? I (Quuador) and some others explain that here in a recent question on the Cubers-reddit:
What exactly causes 4x4 parities?

$\endgroup$

Your Answer

By clicking “Post Your Answer”, you agree to our terms of service, privacy policy and cookie policy

Not the answer you're looking for? Browse other questions tagged or ask your own question.