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A long time ago there lived a wise man. Many people used to call him, & still call him, a wizard, a genius!

He had many, in fact countless friends! One day with some of those friends he formed a union. All these people were very famous & important in their community. Over time the equation changed among them & the union went under transformation to come out in its most appealing form. This union got so famous that it became the identity for that man & vice versa.

At this time the union consisted of 7 people, 5 main members & 2 helpers!

The following is a description of all the members:

Member 1 :
An unpredictable guy, the wizard's adopted son, who was a prominent & important figure in the court of an English warlord!

Member 2 :
This was actually an imaginary guy & as per our wizard he came from ancient Greece.

Member 3 :
Another crazy guy, from somewhere in Asia. It was believed that he came from some sort of spiritual realm.

Member 4 :
This guy is a representative of his people as well as this union. He was an old & ancient fellow, and nobody knew where he came from, though some people believe he attained this current status in India.

Member 5 :
Another old guy from India, who had the look of an ancient Himalayan yogi & claimed to hold the truth about whole cosmos.

And the helpers are:

Helper 1:
He was given the task of keeping a positive atmosphere intact in the group.

Helper 2:
He was given the task of keeping equality among all the members.


Now tell me,

Who is this wizard?
Who are these people?
What is this Union?

Note : This wizard refers to a real world person.

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  • $\begingroup$ Are the 5 members and 2 helpers in addition to the wizard, or is the wizard one of them? Also, are they all real-world people, or just the wizard? $\endgroup$ Apr 16, 2017 at 13:21
  • $\begingroup$ @randal'thor no wizard is not one of them, and only wizard is a real person! $\endgroup$
    – user4956
    Apr 16, 2017 at 13:32
  • $\begingroup$ @Silenus wizard is a real man, all other things are some entities which are not human but one way or other we use those! $\endgroup$
    – user4956
    Apr 16, 2017 at 19:10

2 Answers 2

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The wizard is

Leonhard Euler

and his "union" is

the famous equation $e^{i\pi}+1=0$.

The two "helpers" are

the + and = symbols

and the five others are

the actual numbers involved.

Here are my best guesses at how the clues work. Some of them are not very confident guesses.

An unpredictable guy, the wizard's adopted son, who was a prominent & important figure in the court of an English warlord!

This must be $e$, named of course for the "wizard" Euler and "unpredictable" because irrational. (Either because the digits look random, though actually that isn't implied by irrationality, or because irrational people may be unpredictable.) In comments, OP indicates that the English warlord is in fact another mathematician. Well, pretty much any mathematican in the last 300 years will have made much use of $e$. Newton? (Co-discoverer of the calculus, from which $e$ emerges very naturally.) Taylor? (The exponential function is strongly associated with its nice simple Taylor series.) I hope it isn't Napier, pioneer of logarithms, because Napier was Scottish and not English. Nor, because he too was Scottish, Maxwell (nothing to do with logarithms but plenty of "E"s in his work for entirely different reasons.) Perhaps the word "warlord" is a hint, but I have completely failed to figure out how. (Lots of mathematicians have done military work; hard to see how to pick out a particular one.) ... Or maybe "from the same profession" doesn't mean the warlord was a mathematician. Perhaps e.g. it refers to a "profession of faith"; Euler was a Christian, as we know from the silly story about him and Diderot, so perhaps our English chap was notably religious. I dunno.

This was actually an imaginary guy & as per our wizard he came from ancient Greece.

Presumably this is $i$ ("imaginary"). I've no idea in what sense "per our wizard he came from ancient Greece": I think Euler consistently wrote $\sqrt{-1}$ explicitly rather than (as some occasionally do) $\iota$, and the ancient Greeks certainly didn't have complex numbers. The letter $i$ is, I guess, derived from Greek $\iota$, but again I don't think Euler used it.

Another crazy guy, from somewhere in Asia. It was believed that he came from some sort of spiritual realm.

It seems this must be $\pi$, but I don't understand how this comes from Asia. (Though some of the earliest numerical approximations to it are Chinese.) $\pi$ is, though, a transcendental number, which is close enough to "spiritual" for our purposes here.

This guy is a representative of his people as well as this union. He was an old & ancient fellow, and nobody knew where he came from, though some people believe he attained this current status in India.

This must be either 0 or 1. Probably 1, perhaps with a suggestion of "one man, one vote" ("representative of his people"). Our numerals are of Indian origin.

Another old guy from India, who had the look of an ancient Himalayan yogi & claimed to hold the truth about whole cosmos.

If the previous one is 1 then this must be 0 (which definitely comes from India; more specifically, from Brahmagupta in what we parochially call the seventh century). The last bit might fit better if this one is 1 ("all is one"...) but it looks to me as if the numbers are being listed in the order of their appearance in the usual form $e^{i\pi}+1=0$ of the formula, in which case this must be 0. I suppose some people have claimed that our whole world is some sort of illusion, which would make 0 kinda-sorta hold the truth about the whole cosmos.

In comments below, Silenus suggests

putting #4 and #5 the other way around, 0 being "representative" because both sides of the equation are 0 and 1 for the same "all is one" reason I mentioned above -- and also because the numeral 1 is thin, like a Himalayan yogi! This could well be right; I can't work out whether I find these reasons more or less persuasive than the fact that otherwise the numbers seem to be "in order of appearance".

Things I'm most conspicuously confused by:

Who's the "English warlord", of the same profession as Euler, whose "court" prominently includes $e$? In what sense is $i$ Greek or $\pi$ Asian? If 0 and 1 appear in that order, in what sense is 0 "representative of his people"? If in the other order, why does 0 claim "to hold the truth about whole cosmos"?

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  • $\begingroup$ Member 5 = '1', which can be traced back to Indian glyphs, and which claims to hold the truth about whole cosmos (everything is one). $\endgroup$
    – DyingIsFun
    Apr 17, 2017 at 2:18
  • $\begingroup$ Yes, I wondered about that, but I think it works better if the fourth and fifth are 1 and 0 in that order. (For the avoidance of doubt, my explanations and Silenus's comment above were written independently, and in particular neither of us cribbed "all/everything is one" from the other.) $\endgroup$
    – Gareth McCaughan
    Apr 17, 2017 at 2:23
  • $\begingroup$ Member 4 = '0', makes sense as representative of the union (i.e. equation), since both sides equal zero. $\endgroup$
    – DyingIsFun
    Apr 17, 2017 at 2:24
  • $\begingroup$ You could be right. I don't find 4 and 5 terribly convincing either way around. (Actually, there's lots I find less than fully convincing; I'm not sure whether it's just that a lot of the text is there for "flavour" only or whether I'm missing things.) $\endgroup$
    – Gareth McCaughan
    Apr 17, 2017 at 2:26
  • $\begingroup$ I agree. The fact that Member 5 is characterized as resembling a Himalayan yogi also suggests to me that it is '1' (the evoked image is one of thinness). $\endgroup$
    – DyingIsFun
    Apr 17, 2017 at 2:28
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Probably wrong because my wizard is a chimera, but here's my guess:

Wizard: Banach-Tarski
Members: The 5 non-measurable sets
Union: 3-dimensional solid ball
Helper 1: The Free Group
Helper 2: Axiom of Choice

It certainly had to be a set-theoretic puzzle (at least in my mind) since it mentions fun words such as 'countless', 'union', and 'equation'.

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  • $\begingroup$ +1 you have managed to get one thing right, most general one :) But no this is not answer, your answers to question does not fit and you have not explained it! $\endgroup$
    – user4956
    Apr 17, 2017 at 1:19

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