# Days and Lectures logic puzzle

A school is organizing guest lectures on three different subjects:

• Robotics
• English
• General Aptitude

The event is taking place over three days.The eight lectures are named P,Q,R,S,T,U,V and W,

• Robotics and English are to be covered in three lectures each while the remaining lectures are for general aptitude
• Lecture P, R and S to be on different days
• Lecture V and W should come on the same day
• Lecture Q cannot be put up with P, W and S
• Q and U lectures happen on the same day
• Lecture P is one Robotics and is held one day before R
• Lecture R cannot be on the last Day
• There are at least 3 lectures on day 1

I don't know how to solve it and please anyone guide me the steps, How to proceed these type of sum, which have to take as the first step

There seems to be quite a bit of missing information. Also I am not sure what your question is as none were asked. But here is all the info that CAN be deduced with what you wrote.

First, P R S are on different days.
[P][R][S]
Then Q cannot be with P or S.
[P][R,Q][S]
Then U must be with Q.
D1: [P][R,Q,U][S]
P is before R and R is not last. So the current order of days is correct.
D1: [P], D2: [R,Q,U], D3: [S]
There must be 3 lectures on day 1, Lecture V and W are on the same day and only 3 lectures left to place so V and W must be in day 1.
D1: [P,V,W], D2: [R,Q,U], D3: [S]
I assume that lectures on the same subject must be on different days(?) SO there must be at least 2 lectures everyday.
D1: [P,V,W], D2: [R,Q,U], D3: [S,T]
P is a robotic lecture, and there is no general aptitude lecture on day 3(?)

• how you are putting V ,W is on Day1, why it cannot be on day 3 – Learning user Apr 3 '17 at 2:50
• @Learninguser I thought it was obvious when I said 3 lectures must be on day 1, but added more info to clarify. – stack reader Apr 3 '17 at 2:53
• i have answer for this question, do you want to see@Stack reader – Learning user Apr 3 '17 at 3:03
• Your answer is correct, but finally they added lecture T can happen on anyday,But your explanation is very good,well done @Stack reader – Learning user Apr 3 '17 at 3:06