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There are three of me in every perfect circle. Yet when divided into four identical arcs my number shrinks to two.

What am I?

Hint:

Originally asked as:
There are three of me in every perfect circle. Yet when divided into four identical arcs my number shrinks to two.

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You are

the letter C.

Explanation:

in every "perfect circle", the letters C and E (and no others) each appear exactly three times. E appears once in "four identical arcs", but C appears twice. So the answer must be C.

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  • $\begingroup$ That was quick. Too easy? Thoughts on how to perhaps disguise the answer better? $\endgroup$ – Zymurge Dec 18 '16 at 23:15
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    $\begingroup$ @Zymurge The trouble with puzzles like this is that once you've seen one, every new one of the same type is easy. Any puzzler who already has this idea in their repertoire will look for a single-letter answer as soon as they see something like "there are $n$ of me in X", and it will only take seconds to identify the right solution. $\endgroup$ – Rand al'Thor Dec 18 '16 at 23:20
  • $\begingroup$ Some people are just really good at riddles. This riddle is by no means easy at all. $\endgroup$ – greenturtle3141 Dec 18 '16 at 23:21
  • $\begingroup$ If I un-bolded the keywords, would that help hide the answer. My thinking was that if I didn't call out the specific words somehow, it'd be too arbitrary. $\endgroup$ – Zymurge Dec 18 '16 at 23:22
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    $\begingroup$ @zymurge I have to agree with rand here. As soon as I saw "# in word" I just counted letters and there was "C"....then I scrolled down and it was already answered. So not a bad puzzle - just a well known format that is easily solved by those who know the format. $\endgroup$ – LinkBerest Dec 19 '16 at 11:46

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