There are two sets. The last card of the second is unknown. The first set is 5, 6, and 10. The second set is 7, 2, and ?

What card is the question mark hiding?

I'm too awful at math to figure it out myself. Just wanna know the answer so I can go "ooooh. I get it"


closed as too broad by Peregrine Rook, IAmInPLS, Gamow, Mithrandir, Wu33o Dec 5 '16 at 16:24

Please edit the question to limit it to a specific problem with enough detail to identify an adequate answer. Avoid asking multiple distinct questions at once. See the How to Ask page for help clarifying this question. If this question can be reworded to fit the rules in the help center, please edit the question.

  • 4
    $\begingroup$ This is basically a guess what I'm thinking problem, anything could work with some explanation $\endgroup$ – boboquack Dec 5 '16 at 2:15
  • $\begingroup$ I think it's meant to be like "If 5 and 6 equals 10, what does 7 and 2 equal?" $\endgroup$ – Oliver Dec 5 '16 at 3:14
  • 1
    $\begingroup$ Where did you get this from? $\endgroup$ – greenturtle3141 Dec 5 '16 at 3:16
  • $\begingroup$ @Oliver that's still broad $\endgroup$ – boboquack Dec 5 '16 at 4:42
  • $\begingroup$ I think it's 3 because we have (10,7), (5,2) and so (6,3) and no other combo works. $\endgroup$ – JonMark Perry Feb 26 at 17:27

This answer is an attempt to illustrate how broad the question is to show why this is a bad question.

Here we go, in no particular order.


$5+6-1=10$, so $7+2-1=8$


$\frac{5\times6}{3}=10$, so $\frac{7\times2}{3}=4.666...$


$|5-6|\times10=10$, so $|7-2|\times10=50$


$5-6+11=10$, so $7-2+11=16$


$5.6+4.4=10$, so $7.2+4.4=11.6$


$\frac{5^6\times2}{9375}=10$, so $\frac{7^2\times2}{9375}=0.01045333...$

The last one is ridiculous on purpose - it serves to illustrate the point that almost anything could be an answer.


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