Replace each letter with a digit between 1 and 8 to make the equation
$XAB + YZCD = ZEXY$ true. Each letter represents a different digit.
Bonus question: How many solutions are there in total?
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I've got another one (by which I mean another four):
Solutions come in groups of four, because we can switch $A~$↔$~C$ and $B~$↔$~D$,
so we could also have $A=8,~C=5$ and/or $B=4,~D=2.$
I believe that Sid's answer(s) and mine are the only possible ones; i.e., there are eight solutions.
There could be more, but in base 10, I see 4 solutions:
A=1 B=2 C=7 D=3 E=4 X=8 Y=5 Z=6 5673+812=6485
A=1 B=3 C=7 D=2 E=4 X=8 Y=5 Z=6 5672+813=6485
A=7 B=2 C=1 D=3 E=4 X=8 Y=5 Z=6 5612+873=6485
A=7 B=3 C=1 D=2 E=4 X=8 Y=5 Z=6 5613+872=6485
Clarification - I had initially posted an answer that had 0 in it, but I hadn't read the rules and so, I have changed my answer.