We're not talking about the motorsport, but about one of the most famous formulae in mathematics. It's also slightly rearranged and in a form of the rebus: No hint here


The answer is a single letter.

  • $\begingroup$ We are assuming log and ln are different, right? $\endgroup$
    – Sid
    Nov 9, 2016 at 18:01
  • $\begingroup$ @Sid Not really. $\endgroup$
    – pajonk
    Nov 9, 2016 at 18:08
  • $\begingroup$ @Sid i believe it makes no difference here. The formula is universal if memory serves right. $\endgroup$
    – user64742
    Nov 9, 2016 at 18:50
  • 1
    $\begingroup$ @TheGreatDuck Actually it makes difference. The base of the logarithm plays a significant role here. $\endgroup$
    – pajonk
    Nov 9, 2016 at 19:00
  • $\begingroup$ I thought all logs of that value coincided with the same result. My bad. $\endgroup$
    – user64742
    Nov 9, 2016 at 19:10

2 Answers 2


The answer is


As observed by Beastly Gerbil, the first half of the rebus is



January is the first month and an eye is the universal rebus of 'i'.

The image of the log represents


The thermometer and the coal represent



30.2° F is -1° C. The coal appearing beneath the line represents removing the 'C' because coal is carbon, whose elemental symbol is 'C'.

So the second part becomes


We know that

$\log(-1) = i\pi$ from Euler's Equation, $e^{iπ} + 1 = 0$,

so the second part is


Given the first part we end up with:


which is just



Currently unsure about the last part but the first part is

$\frac1i \log \left(\frac{30.2?}{?}\right)$


January is the first month and its over an eye and then there is a log and it then might be 30.2 because that is the number shown


Well done @Silenus, who worked out that

The last part is -1 because 30.2 F is -1 C (Coal indicates C). This means that the equation is:

$\frac1i \log (-1)$

Which is


Which is simply


  • 1
    $\begingroup$ I am not sure what famous formula that represents... $\endgroup$
    – Sid
    Nov 9, 2016 at 17:39
  • $\begingroup$ It will end up as a value which will equate to a mathematical letter @Sid $\endgroup$ Nov 9, 2016 at 17:40

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