I have a set of what I believe to be 4 (X,Y) points turned into a blob of hex
like so: 0x000080BFA8AAF340000080BF031AFE40FFFF3F41010D6741FFFF3F4153D56141
Can you decipher and explain the encoding?
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$\begingroup$ Do you know how many X,Y points there are in there? $\endgroup$– BohemianOct 31, 2016 at 20:10
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$\begingroup$ I believe there to be 4 $\endgroup$– jth41Oct 31, 2016 at 20:11
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3 Answers
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The numbers make more sense when interpreted as 32-bit IEEE 754 floating-point numbers, stored in little-endian byte order. The number -1 in this format has a specific value and it would be surprising to find its little-endian byte representation 0x000080BF anywhere else.
-1. , 7.614582
-1. , 7.9406753
11.999999 , 14.440675
11.999999 , 14.114581
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Incredibly basic, but I get the following four points:
- (32959, 2829775680)
- (32959, 52100672)
- (4294917953, 17655617)
- (4294917953, 1406492993)
Basically, just turn each coordinate from DEC to HEX and concatenate them all after the 0x prefix. Not really a cipher, but there ya go.
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$\begingroup$ ^vote with questions: Do the coordinates outline a figure? Might the coordinates be floating point? GPS? $\endgroup$– humnOct 31, 2016 at 21:20
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Interpreting the text as 8 32-bit hexidecimal numbers, and using 2's compliment, you get:
+32959, -1465191616
+32959, +52100672
-49343, +17655617
-49343, +1406492993
I don't know if that helps.
They could be lat/long pairs, but I can't see how to convert the number raw value to a lat/long range, especially given the large values.
