I have a set of what I believe to be 4 (X,Y) points turned into a blob of hex

like so: 0x000080BFA8AAF340000080BF031AFE40FFFF3F41010D6741FFFF3F4153D56141

Can you decipher and explain the encoding?

  • $\begingroup$ Do you know how many X,Y points there are in there? $\endgroup$
    – Bohemian
    Commented Oct 31, 2016 at 20:10
  • $\begingroup$ I believe there to be 4 $\endgroup$
    – jth41
    Commented Oct 31, 2016 at 20:11

3 Answers 3


The numbers make more sense when interpreted as 32-bit IEEE 754 floating-point numbers, stored in little-endian byte order. The number -1 in this format has a specific value and it would be surprising to find its little-endian byte representation 0x000080BF anywhere else.

-1.       ,  7.614582  
-1.       ,  7.9406753 
11.999999 , 14.440675  
11.999999 , 14.114581 

Incredibly basic, but I get the following four points:

  • (32959, 2829775680)
  • (32959, 52100672)
  • (4294917953, 17655617)
  • (4294917953, 1406492993)

Basically, just turn each coordinate from DEC to HEX and concatenate them all after the 0x prefix. Not really a cipher, but there ya go.

  • $\begingroup$ ^vote with questions: Do the coordinates outline a figure? Might the coordinates be floating point? GPS? $\endgroup$
    – humn
    Commented Oct 31, 2016 at 21:20

Interpreting the text as 8 32-bit hexidecimal numbers, and using 2's compliment, you get:

+32959, -1465191616
+32959, +52100672
-49343, +17655617
-49343, +1406492993

I don't know if that helps.

They could be lat/long pairs, but I can't see how to convert the number raw value to a lat/long range, especially given the large values.


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