8
$\begingroup$

I'm trying to solve this puzzle and need some help with the solution:

assembled version

These are the pieces:

puzzle pieces

The size is: 60mm x 40mm x 10mm.

Any help appreciated.

How do you solve this?

$\endgroup$
7
  • $\begingroup$ Look around here: puzzling.stackexchange.com/a/2692/29343 $\endgroup$
    – Matsmath
    Oct 27, 2016 at 8:25
  • 1
    $\begingroup$ It's a completely different puzzle $\endgroup$ Oct 27, 2016 at 8:26
  • $\begingroup$ Oh God this is looking like the Gordian knot... $\endgroup$ Oct 27, 2016 at 11:21
  • 1
    $\begingroup$ I have one similar to this, but it doesn't have the little notches inside $\endgroup$
    – dcfyj
    Oct 27, 2016 at 12:21
  • $\begingroup$ @YuryFedorov Is this a puzzle you possess? You took the photos? If so, could you share the measurements? $\endgroup$
    – Alenanno
    Oct 27, 2016 at 13:13

3 Answers 3

6
$\begingroup$

This looks like a variation of Chen's 6 Board Burr #2. An easier variation even, as the 5th piece in your picture should be "whole" like the 3rd one:

enter image description here

Solution (with pictures): http://www.puzzlewillbeplayed.com/6BoardBurr/Chen/2/solution.html

$\endgroup$
1
  • 2
    $\begingroup$ Right now this counts as a link only answer. $\endgroup$
    – kaine
    Oct 29, 2016 at 18:23
2
$\begingroup$

Here is another solution, step by step

http://www.mywoodenpuzzles.com/#!/link_knot_six/solution/step_1_of_16

$\endgroup$
0
$\begingroup$

Hm, looking at it, if we number the pieces
1 2 3
4 5 6

We know that the puzzle ends up with three pairs of pieces interlocked, and I'm fairly certain those pairs are 1&2, 3&5, and 4&6, because the notches in 1&2 and 4&6 match each other.

I could be wrong but I hope this helps?

$\endgroup$
2
  • 1
    $\begingroup$ To me, matching notches makes it more likely to not be paired together. $\endgroup$
    – dcfyj
    Oct 27, 2016 at 12:26
  • $\begingroup$ I agree. I think the last two pieces to place should be 4 & 6 with 6 being the very last piece. The first are 3 & 5. Thus, you should place 1&2 inside 3&5 and then get 4&6 in. $\endgroup$
    – Trenin
    Oct 27, 2016 at 13:46

Your Answer

By clicking “Post Your Answer”, you agree to our terms of service and acknowledge that you have read and understand our privacy policy and code of conduct.

Not the answer you're looking for? Browse other questions tagged or ask your own question.