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How can I rearrange the domino tiles below so that all vertical columns has 0,1,2,3,4,5,6. While all the horizontal rows has 0,1,2,3,4,5,6 + duplicate ?

enter image description here

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  • $\begingroup$ I'm not sure, what do you mean with "+duplicate"? Could you clarify the question? $\endgroup$
    – Alenanno
    Commented Oct 19, 2016 at 19:42
  • $\begingroup$ Disclaimer: I don't know how $\endgroup$
    – TSLF
    Commented Oct 19, 2016 at 19:44
  • $\begingroup$ @TSLF if this isn't your puzzle you need to credit the source otherwise it is plagiarism $\endgroup$ Commented Oct 19, 2016 at 19:44
  • $\begingroup$ I managed to do all vertical but I am not sure if this is possible. $\endgroup$
    – TSLF
    Commented Oct 19, 2016 at 19:59
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    $\begingroup$ By duplicate do you mean you can have one duplicate value. For example row 1 will contain (0,1), (2,3), (4,5),(6,4) where 4 is a duplicate or (0,1), (2,3), (4,5),(6,6) where 6 is a tile with the same value on both sides. And are you supposed to have 2 (5,6) tiles or should the last one be (6,6) $\endgroup$
    – gtwebb
    Commented Oct 19, 2016 at 20:15

1 Answer 1

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As noted in the comments to the question, the tiles in the picture form a standard set except for an extra 5/6 and a missing 6/6. If we assume the picture to be correct,

It's impossible, as there aren't enough sixes to cover all 8 columns.

Otherwise, making the assumption that we are supposed to arrange a standard set:

Any double already creates a duplicate, so we have to have one double in each row. Therefore, I started by placing all doubles in the first column. To keep the pattern going, I arranged all tiles with a difference of 1 or 6 in the second column, differences of 2 or 5 went in the third column, and finally 3 or 4 in the fourth column:

 00  23  46  51
 11  34  50  62
 22  45  61  03
 33  56  02  14
 44  60  13  25
 55  01  24  36
 66  12  35  40

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  • $\begingroup$ Its corrected , (5,6) now (6,6) $\endgroup$
    – TSLF
    Commented Oct 20, 2016 at 17:02

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