A never ending party is being held at a local mansion. The host is very rich and his success is because of one thing — his famous recipe for Spaghetti!

The only guests that may attend are people who correctly reply to the guard at the door.

Here's where you come in. You and a friend are trying to steal this recipe. You sneak by and listen to the passwords.

The first guest arrives. The security says "1 and 1", and the guest replies "1".

The second guest arrives. The security says "2 and 2", the guest replies "2".

The third guest arrives. The security says "3 and 3", the guest replies "3".

Your friend thinks he's got it all figured out, he thought that it was a crappy logical problem and at last he would have a glimpse of the hidden recipe so he walks up to the door and the security says "4 and 4". He was very confident and whispered that at last he will not be terminated which happened in the previous episodes, the security heard him and changed the question to "4 and 7". Your friend was devastated and he knew what would happen so he grabbed a pill that he hid in his pocket and he ate it and died.

Another guest arrives, you seem to get the same pattern, security says "1 and 7" and he says "7" to get in.

Another guest arrives, you seem to get the same pattern, security says "8 and 3" and he says "8" to get in.

You now walk up to security and get "4 and 7", what is the correct response?

hint(worthless hint but still accurate):

Another guest arrives, you seem to get the same pattern, security says "4 and 4" and he says "4" to get in.


Another guest arrives, you seem to get the same pattern, security says "0 and 1" and he says "0" to get in.


This is another problem that doesn't include computations in it


You need to merge the numbers but not in the mathematical way or not in a number words, just the number itself

final and a giveaway hint


i think this one is an easy one since that it was already used in the previous versions

  • $\begingroup$ Oh. "The Security to the Party [Part 3.5e+1442553]" $\endgroup$ – nicael Nov 13 '14 at 9:32
  • $\begingroup$ yeah, guess that i am not really good in math... that's why my puzzles do not include maths :D $\endgroup$ – Kelvin Barsana Nov 13 '14 at 9:34
  • $\begingroup$ I mean, how many posts in this series are going to come? :) $\endgroup$ – nicael Nov 13 '14 at 9:36
  • $\begingroup$ until we get bored with it perhaps $\endgroup$ – Kelvin Barsana Nov 13 '14 at 9:46
  • 1
    $\begingroup$ Probably until we create a securitytoparty.stackexchange.com :P $\endgroup$ – skv Nov 16 '14 at 14:24

The answer is



Overwrite number on each other in 7 segment display
Write 8 over 3 to get 8
Write 1 over 0 to get 0

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  • 1
    $\begingroup$ thumbs up :DDDD $\endgroup$ – Kelvin Barsana Nov 13 '14 at 9:49
  • 1
    $\begingroup$ Nice puzzle @KelvinBarsana! $\endgroup$ – A E Nov 13 '14 at 9:58
  • $\begingroup$ Actually this is not the standard way a 9 is usually written on a 7-segment display. $\endgroup$ – ThePopMachine Nov 13 '14 at 20:42
  • $\begingroup$ @MohitJain: I accept that this is the right answer; I'm just saying the puzzlecrafter was technically incorrect. 5+(7,1 or 4)=9 or 2+5=8 might have been better questions. $\endgroup$ – ThePopMachine Nov 14 '14 at 15:24
  • $\begingroup$ Please do not post an answer where all the content is hidden in spoiler markup. Your answer should make sense and be distinguishable from another answer to a reader who cannot or chooses not to read the spoiler block. $\endgroup$ – Gilles 'SO- stop being evil' Nov 16 '14 at 11:15

My (trollish) answer:

First, I save the game and answer 4. If I get in, I am done. If I die, I should load my saved game data back and try 7 instead.

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I think the answer is

7. Answer is the one which is bigger one b/w guard said.

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Could it be this?

4, if the first number is an even number, you take the first number, if it's odd you take the second (0 is an even number).

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7, count the characters of the first number (for example: two = 3 characters)
So you get 1 - 3 = -2
one 1 = -2
two 2 = -1
three 3 = -1
one 7 = 4
eight 3 = -2
four 7 = 2
if the result is positive then the right number is correct

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  • $\begingroup$ Could someone fix my spoilers D: $\endgroup$ – Frunk Nov 13 '14 at 9:37
  • $\begingroup$ add this '>!' instead of this '>' $\endgroup$ – Kelvin Barsana Nov 13 '14 at 9:38
  • $\begingroup$ i can't seem to understand your answer, did you include a computation for that? $\endgroup$ – Kelvin Barsana Nov 13 '14 at 9:42
  • $\begingroup$ @KelvinBarsana I edited a bit, hope you understand it. $\endgroup$ – Frunk Nov 13 '14 at 9:44
  • $\begingroup$ thumbs up for trying though $\endgroup$ – Kelvin Barsana Nov 13 '14 at 9:53

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