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First crack at rebus (Suggestions are welcome)

enter image description here

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    $\begingroup$ Wow... there are downvotes as soon as I posted the question(and again without reasons)...almost made me think that it is system generated response $\endgroup$
    – smriti
    Commented Sep 19, 2016 at 11:00
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    $\begingroup$ im still working on the solution but thanks to this post i learnt the origin for the Peace simbol ☮ $\endgroup$
    – lois6b
    Commented Sep 19, 2016 at 11:15
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    $\begingroup$ I honestly have no idea why this was downvoted, it seems legit. The only reason I can think of is the unoriginal title, but that shouldn't be why someone up votes/ down votes $\endgroup$
    – Areeb
    Commented Sep 19, 2016 at 11:15
  • $\begingroup$ the title say: 'play' and my lord is GabeN ... maybe is something there $\endgroup$
    – lois6b
    Commented Sep 19, 2016 at 13:05

3 Answers 3

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The answer is

To infinity and beyond! (Buzz Lightyear from Toy Story)

The colon is used in comparisons to mean "to". while(1) produces an infinite loop. The Venn diagram adds the word "and". The final bit is "Bey on D" because Beyonce?


Previous solution: Okay, here's my guess:

:O (surprised face)

It starts with a colon, then shows a Venn diagram indicating the intersection between two things. The way I read those things are "loop" (while(1) produces a programming loop) and "go" ($\frac{god}{d} = go$). The intersection of these two words is the single letter "o".

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    $\begingroup$ but maybe is not correct cause you dont need to "devide" by d because god works also with the intersection ... $\endgroup$
    – lois6b
    Commented Sep 19, 2016 at 11:37
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    $\begingroup$ OMG!! Very nice explanation! +1(for finding intersection between loop and go! I did not even think about that while posting),Unfortunately not the answer. $\endgroup$
    – smriti
    Commented Sep 19, 2016 at 11:41
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    $\begingroup$ I think you're right with the edit. Although Bey on D because Beyonce? ._. $\endgroup$ Commented Sep 19, 2016 at 13:27
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    $\begingroup$ @AurelBílý Ha, I thought the exact same thing, but it's probably in reference to Serapis... who I've definitely never heard referred to as merely "Bey?" (Bey is the queen, not the lord.) $\endgroup$
    – Will
    Commented Sep 19, 2016 at 13:29
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    $\begingroup$ maybe its bee because my lord = queen bee, also reference to lord - lorde ? so ''bee on d'' $\endgroup$ Commented Sep 19, 2016 at 13:37
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Partial Answer:

While(1) indicates:

infinite loop, here 1 means true

enter image description here

indicates:

Semaphore(a system of sending messages by holding the arms or two flags or poles in certain positions according to an alphabetic code). It indicates symbol "D".

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  • $\begingroup$ That's only half of "peace" though $\endgroup$
    – Will
    Commented Sep 19, 2016 at 12:31
  • $\begingroup$ Than is not "peace" symbol, though you are close with the while(1) $\endgroup$
    – smriti
    Commented Sep 19, 2016 at 12:33
  • $\begingroup$ On reverse search, the symbol indicates peace. $\endgroup$
    – KSR
    Commented Sep 19, 2016 at 12:36
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    $\begingroup$ perhaps it isn't needed. semaphores are terminology in programming, same as while loops. maybe it has a double meaning. $\endgroup$ Commented Sep 19, 2016 at 12:40
  • $\begingroup$ @Bulldogg6404.. Yes we have to crack it.. $\endgroup$
    – KSR
    Commented Sep 19, 2016 at 12:41
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Some possible interpretations of the Venn Diagram:

- while(1) is the same as "always"
- @Ian_MacDonald discovered the right side of the diagram could represent "$god/d$ = $go$"
- the intersection would then be "Always on the go."

I have no idea what the two dots on the left mean.

If it is, in fact, a colon, it could mean that the colon (double meaning) is always on the go, but that is a rather unsanitary possibility and I hesitate to think it could be the intended answer.

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  • $\begingroup$ 'my lord' represents a different thing. Also think of while(1) as a programmer $\endgroup$
    – smriti
    Commented Sep 19, 2016 at 12:32
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    $\begingroup$ being that i am a programmer, i cannot think of while(1) as anything but a programmer xD I'll give it some more thought $\endgroup$ Commented Sep 19, 2016 at 12:34

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