On my way to the supermarket, I walk at a certain speed. I want my average speed for the back and forth trip to be twice that speed. At what speed should I go back home to reach that goal?
Let x be distance between home and market , t1 time for going forward and t2 for coming back.
p is natural number
$$2x/(t1+t2)=2p kmph $$
Divide both eqn => $$ (t1 +t2)/(t1) =1 $$
**but t2 becomes 0 , so not possible solution.
answer is not possible..