Which of these four images is the result to the above and why?
3 Answers
The answer is
ANDROMEDA. The picture of the strawberries clues "ROT" and the nautilus clues the Fibonacci sequence. So to decipher the grid, you use the ROT-n cipher on each letter, where n changes according to the Fibonacci sequence: 0, 1, 1, 2, 3, 5, 8, 13, 21.
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$\begingroup$ I was trying this technique for so long, but starting at 1 instead of 0. When you posted the latest comment to your question is when I realized what I was doing wrong. $\endgroup$– C. WoodsAug 4, 2016 at 15:36
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1$\begingroup$ Damnit. I knew as soon as it was confirmed as andromeda but didn't have time to write out the answer. $\endgroup$ Aug 4, 2016 at 15:37
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1$\begingroup$ @C.Woods I thought of starting it from 1,1, but Fibonacci sequence starts with 0,1 according to Google, so decided to do it this way... Also chose Mona Lisa's image to mislead the people, don't know if it was a good idea, but it worked pretty well :)) $\endgroup$– Gintas KAug 4, 2016 at 15:40
I, too think it's the Mona Lisa:
Both the shape of the Nautilus Pompilius and distance/pattern of strawberry seeds are examples of the golden ratio, as is the Mona Lisa(and other Da Vinci Paintings AFAIK) (Partial credit to lois6b). The letter puzzle could be considered a code. I think the riddle refers to "The Da Vinci Code".
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$\begingroup$ mhh what intrigues me is that, the letters are one part of the summation and the other part is RottenStrawberries together with shell.. $\endgroup$– lois6bAug 4, 2016 at 14:04
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$\begingroup$ A couple of hints for you: The solution is not related to Da Vinci. Different letters would result in a different solution. $\endgroup$– Gintas KAug 4, 2016 at 15:21
I'd say:
The galaxy.
Because:
It contains stars, which are small shiny points (like the small seeds in the strawberry), arranged in a spiral (like the shell) and their names usually contains Greek letters (like Alpha Centauri, Gamma Tauri and so on).
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rebus
tag be appropriate too? $\endgroup$cipher
tag, it was supposed to be one of the hints :) $\endgroup$