A kind of arbitrary solution to a - so far - arbitrary puzzle:
- I assume one square represents one "pixel" or one "field".
- I assume one may not step on BLACK and DARK GREEN squares.
- I assume the move has to be like the chess knights.
- I assume we have to start on the Yellow and end on the red dot.
With all these assumptions, and because there is no rule-set given, this would be my solution:
I should add, that while the answer above is a bit of a joke, I did take the puzzle serious and was/am searching for some more obvious relationship. This is what I have thought so far:
- The puzzle should need the color information somehow, otherwise it is all just a huge, red-herring. (Any only red is relevant.)
- If BLACK squares would be allowed to be moved on, this would be trivial, so I rule that out.
- If all NON-BLACK sqaures can be moved on, this would be trivial, so I rule that out.
- If we are allowed to move on the DARK-GREEN squares, we could basically move nearly everywhere, so I rule that out.
- Any CONTINUOUS move has to step either on BLACK or DARK GREEN, so I rule them out.
- Trying to utilize the PEANUT pixels: The rect of pixels is 23x4 or 28x10 depending if you just cut the text or the whole white area. Unfortunately the colour-dots form a grid of 14x8 (or 14x9), so I can see no relationship.
- I followed the idea of "teleporting" fields, assuming pixels of same color are linked. Unfortunately, the very pixels next to the yellow entrance (both the pale yellew and the light green) are of a colour nowwhere else to be found (exactly), so that fails...
It was suggested that the colours in the pixels could be shown in their RGB hex representation with considering the zeros as wall. Doing this with the image, assuming one square is the "natural" resolution of the image, gives:
which does not lead to a useful maze.
Another observation is, that - starting with the yellow pixel on the right - neighbouring pixels always seem to have one channel (red/green/blue) with value zero. Unfortunately, this breaks down when coming to the left side, as the red pixel does not neighbour to a colour with one channel being zero.
Also: The pale purple which touches the red pixel is not of the same colour (exactly) as the one given as "allowed" hint...